The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
We are asked to find the proportion of sugar to number of cookies
Sugar = 200g
Number of cookies = 48
proportion of sugar to cookies = 200 : 48
how many cookies he can make with 350 grams of sugar?
let x = number of cookies
proportion of sugar to cookies = 350 : x
equate the <em>proportions</em>
200 : 48 = 350 : x
200/48 = 350/x
cross product
200 × x = 350 × 48
200x = 16800
x = 16800/200
x = 84 cookies
find the number of cookies, y, Ezra can make with x grams of sugar?
y = grams of sugar, x / number of cookies
y = 350/84
y = 4.17x
Therefore,
Ezra can make 84 cookies with 350 grams of sugar
Read more:
brainly.com/question/3796978
Had it in a test the answer is B -<span>Educational services</span>
Answer:
that doesn't make sense.
Step-by-step explanation:
