1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liula [17]
3 years ago
11

The person who answers the question with the mathematical explanation and answer gets 65 points in total if answers correctly an

d marked as the brainliest so DON'T ANSWER WITH AN IDK AND GET FREE POINTS! If the area of a circle of radius 7 cm is 154 sq cm, what is the area of the shaded portion of the figure shown below?

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

Answer:

10.5 squared centimetres.

Step-by-step explanation:

First, find the area of that sector. We are already given that the circle is 154 squared centimetres.

We are given 90 degrees (or one fourth of the circle). Thus, divide 154 by 4 to get the area of the sector (the white area).

The area of the sector is 154/4 or 38.5

We then need to find the area of the square. After that, we can subtract the sector area (the white area) from the area of the square (the total area) to find the area of the shaded section.

The area of the square is 7*7 or 49.

Thus, the shaded portion will be 49-38.5 or 10.5 squared centimetres.

sweet [91]3 years ago
5 0

Answer:

10.5 cm^2

Step-by-step explanation:

The square has area s^2 = (7 cm)^2 = 49 cm^2

The area of the portion is the the area of the square minus the area of 1/4 of the circle.

Area of 1/4 of the circle = 154 cm^2 / 4 = 38.5 cm^2

Area of shaded portion = 49 cm^2 - 38.5 cn^2 = 10.5 cm^2

You might be interested in
It takes one super giant pizza to feed 3 people. If you invite 35 people, how many pizza will you need?
Vilka [71]
Over 9000!!!!!!!!!!!
8 0
3 years ago
Read 2 more answers
The diagonals of a rhombus are 12 in. and 16 in. long. The length of a side of the rhombus is 10 in. What is the height of the r
iris [78.8K]
If d₁ and d₂ are the lengths of the diagonals, the area is given by
.. A = (1/2)*d₁*d₂
.. A = (1/2)*(12 in)*(16 in)
.. A = 96 in²

If b is the base and h is the height, the area is given by
.. A = b*h
We know the values of A and b, so
.. 96 in² = (10 in)*h
.. (96 in²)/(10 in) = h = 9.6 in

The height is 9.6 in.
3 0
3 years ago
The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the
Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

  • a +b +c = 26
  • 2a -b = c -2
  • -3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

_____

The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

6 0
3 years ago
SOMEONE HELP ME ASAP!
lord [1]

Answer:

(-3, 1)

The solution is the point at which both lines intersect.

This is the solution since both lines would have that point and only that ppoint in this type of problem. IN a graph where 2 lines are parralel, there is no solution as they never intersect . on a graph where the 2 lines overlap there is infinite solutions. FInally in a graph like this there is exactly one solution and it is the intersection of both lines

Step-by-step explanation:

6 0
2 years ago
ASAP NEED HELP!!!! ∩ω∩ Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A san
Nikitich [7]

Answer:

Step-by-step explanation:

A. The first inequality is graphed as a shaded area below the solid line with x-and y-intercepts of 7.5 and 5, respectively. The second inequality is graphed as a shaded area above the solid line with x- and y-intercepts of 3.

The solution set is the set of integer-valued grid points one or between the lines.

__

B. The point (5, 1) is included in the solution area. Mathematically, it can be shown to satisfy the two inequalities:

  2(5) +3(1) ≤ 15   ⇒   13 ≤ 15   True

  (5) +(1) ≥ 3   ⇒   6 ≥ 3   True

__

C. The point (5, 1) is in the solution set. It means Michael can purchase 5 sandwiches and 1 hot lunch within his budget constraints. That will provide 6 meals, which is more than the minimum of 3 that he wants to provide.

8 0
3 years ago
Other questions:
  • The volume (V) of a sphere varies directly with the cube of its radius (r). If k is the constant of proportionally, which is the
    14·1 answer
  • M plus three n equals 1 for n
    15·1 answer
  • A triangle with sides 7.5, 10, and 12.5 is a right triangle.
    12·1 answer
  • If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
    11·1 answer
  • Select the correct answer.
    6·1 answer
  • How do you factor out the number 4
    8·1 answer
  • Please help I am struggling with math and this is one of the problems I can’t find a answer to
    12·1 answer
  • five people arrived at the check _ out counter of a hotel at the same time, in how many different ways can the people line up?​
    13·1 answer
  • Find a linear differential operator that annihilates the given function. (Use D for the differential operator.) 4 ex cos 3x
    12·1 answer
  • Can someone help me on these problems and show work
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!