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Liula [17]
3 years ago
11

The person who answers the question with the mathematical explanation and answer gets 65 points in total if answers correctly an

d marked as the brainliest so DON'T ANSWER WITH AN IDK AND GET FREE POINTS! If the area of a circle of radius 7 cm is 154 sq cm, what is the area of the shaded portion of the figure shown below?

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

Answer:

10.5 squared centimetres.

Step-by-step explanation:

First, find the area of that sector. We are already given that the circle is 154 squared centimetres.

We are given 90 degrees (or one fourth of the circle). Thus, divide 154 by 4 to get the area of the sector (the white area).

The area of the sector is 154/4 or 38.5

We then need to find the area of the square. After that, we can subtract the sector area (the white area) from the area of the square (the total area) to find the area of the shaded section.

The area of the square is 7*7 or 49.

Thus, the shaded portion will be 49-38.5 or 10.5 squared centimetres.

sweet [91]3 years ago
5 0

Answer:

10.5 cm^2

Step-by-step explanation:

The square has area s^2 = (7 cm)^2 = 49 cm^2

The area of the portion is the the area of the square minus the area of 1/4 of the circle.

Area of 1/4 of the circle = 154 cm^2 / 4 = 38.5 cm^2

Area of shaded portion = 49 cm^2 - 38.5 cn^2 = 10.5 cm^2

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Answer:

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Step-by-step explanation:

8 0
3 years ago
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(6, - 3, 1) and (8,9,-11) find the angle between the vector​
Svetllana [295]

Answer:

The angle between the two vectors is 84.813°.

Step-by-step explanation:

Statement is incomplete. Complete form is presented below:

<em>Let be (6,-3, 1) and (8, 9, -11) vector with same origin. Find the angle between the two vectors. </em>

Let \vec u = \langle 6, -3, 1 \rangle and \vec v = \langle 8,9,-11 \rangle, the angle between the two vectors is determined from definition of dot product:

\theta = \cos^{-1} \left(\frac{\vec u \,\bullet \,\vec v}{\|\vec u\|\cdot \|\vec v\|} \right) (1)

Where:

\vec u, \vec v - Vectors.

\|\vec u\|, \|\vec v\| - Norms of each vector.

Note: The norm of a vector in rectangular form can be determined by either the Pythagorean Theorem or definition of Dot Product.

If we know that \vec u = \langle 6,-3,1 \rangle and \vec v = \langle 8, 9,-11 \rangle, then the angle between the two vectors is:

\theta = \cos^{-1}\left[\frac{(6)\cdot (8) + (-3)\cdot (9) + (1)\cdot (-11)}{\sqrt{6^{2}+(-3)^{2}+1^{2}}\cdot \sqrt{8^{2}+9^{2}+(-11)^{2}}} \right]

\theta \approx 84.813^{\circ}

The angle between the two vectors is 84.813°.

6 0
3 years ago
When determining the quotient of two numbers written in scientific notation,______the base numbers and______the exponents of the
Elena L [17]
1.) Divide

2.) Subtract
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3 years ago
Kelly got a part time job and had to pay $150 worth of taxes, which was 10% of her monthly payment. How much money did she make
zalisa [80]

Answer:

$1,500

Step-by-step explanation:

To find how much money she made before paying taxes, divide 150 by 0.1:

150/0.1

= 1500

So, Kelly made $1,500 before taxes

3 0
3 years ago
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5x = –25 + 5y <br><br> 10y = 42 + 2x
Novay_Z [31]
To solve this equation there are many ways you can do to solve. One way is to simply substitute one variable for another.

5x = 5y - 25
X = y - 5

10y = 42 + 2x
10y = 42 + 2(y - 5)
10 y = 42 + 2y - 10
8y = 32
Y = 4.

X = y - 5
X = 4 - 5
X = -1.

P(X,y) = P(-1,4). This would be the solution or the point where they would intersect.
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3 years ago
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