Answer:
∪ means the whole numbers which is found in them
B and C have the numbers, 3,7, 6, 9, 2, 5
so, B∪C={2, 3, 5, 6, 7, 9)
Step-by-step explanation:
can i have brainliest if it helped : )
Answer:
Option C.
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space (total person's hemoglobin level of 9 or above with age above 35 years)
y-----> size of the sample space (total person's age above 35 years)
so
In this problem we have
Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)
Let
y------> total person's hemoglobin level between 9 and 11 (person's age above 35)


Find the value of x

substitute the values
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
Answer:
I agree with you,I also think its B
Step-by-step explanation: