Answer:
24 is the GCD of 48,120
plz mark me as brainliest
Answer:
a) 280.4; b) E. Yes, because 300 is greater than mu plus 2 sigma .
Step-by-step explanation:
For part a, we multiply the percentage of murders committed by a firearm by the total number of murders:
0.701(400) = 280.4
This will be the average number of murders by a firearm out of a sample of 400.
Since this is a binomial distribution (two outcomes; independent trials; same probability of success for each trial; and fixed number of trials), the standard deviation is given by
√npq
Since n = 0.701, q = 1-0.701 = 0.299.
This gives us
√(400*0.701*0.299) = √83.8396 = 9.16
This means any unusual values will be less than 2 standard deviations below the mean or more than 2 standard deviations above the mean.
2 standard deviations below the mean will be 280.4-2(9.16) = 280.4-18.32 = 262.08. 300 is not below this value.
2 standard deviations above the mean will be 280.4+298.72. 300 is above this, so it is an unusual value.
Im not sure if it’s right but I tried, sorry
Answer: 30%
Step-by-step explanation:
Let A be the probability of a student opting for mathematics - it consists of either boy opting for mathematics or girl opting for mathematics. As there is "or" we need to sum these probabilities.
![P(A) = P(B)* P(M|G) + P(G)*P(M|G)](https://tex.z-dn.net/?f=P%28A%29%20%3D%20P%28B%29%2A%20P%28M%7CG%29%20%2B%20P%28G%29%2AP%28M%7CG%29)
![P(A) = \frac{1}{2} * \frac{20}{100} + \frac{1}{2} * \frac{40}{100}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%5Cfrac%7B20%7D%7B100%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%5Cfrac%7B40%7D%7B100%7D)
![P(A) = 3/10 = 0.3](https://tex.z-dn.net/?f=P%28A%29%20%3D%203%2F10%20%3D%200.3)
=> 30%