If f(x) = (3x + 7)²
then f(1) = (3(1) + 7)²
= 10²
⇒ f(1) = 100 [OPTION E]
118 handle bars tells us that there's 118 bikes
if all 118 bikes were regular bikes
118*2 = 236
we would be 33 wheels short
118*1 = 118
we would be 17 seats short
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if 101 of the bikes are regular and 17 are tandem
101*1 = 101
17*2 = 34
we would have the right amount of seats
101*2 = 202
17*2 = 34
202 + 34 = 236
we would be 33 wheels short.
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if 17 bikes are tandem, 33 are tricycle, and 68 are regular
17*2 = 34
33*3 = 99
68*2 = 136
we would have the right amount of wheels
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Answer:
There are 68 bicycles, 17 tandem bicycles, and 33 tricycles.
This question isn't hard, it just takes longer since it's based off of guess and check.
Answer:
Step-by-step explanation:
x^2+20=2x move 2x to the left
x^2-2x+20=0
Quadratic formula =
x=1± i√19
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
