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Phantasy [73]
3 years ago
6

le="(1 x^{2000})(1 x)^{1998}=(2x)^{1999}" alt="(1 x^{2000})(1 x)^{1998}=(2x)^{1999}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0
Hello,
x^{2000}*x^{1998}=2^{1999}*x^{1999}\\
==\textgreater\  x^{2000+1998}=2^{1999}*x^{1999}\\
==\textgreater\  x^{2000+1998-1999}=2^{1999}\\
==\textgreater\  x^{1999}=2^{1999}\\
==\textgreater\  x=2



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