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iogann1982 [59]
3 years ago
8

HELP ASAP!!! Worth 50 points! Please give a step-by-step explanation, or you will be reported!

Mathematics
1 answer:
KIM [24]3 years ago
5 0

For all the dogs: you have 2.65+2.46+3.67+2.91 = 11.69%

Now, the probability of getting a chihuahua would be 3.44/11.69=0.2942= 24.92

Step-by-step explanation:

there ya go,,,,,,

.....

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Answer:

n 1932 DeBakey devised the “roller pump,” an essential component of the heart-lung machine that permitted open-heart surgery. He also developed an efficient method of correcting aortic aneurysms by grafting frozen blood vessels to replace diseased vessels.

Works written: The New Living Heart

Born: September 7, 1908, Lake Charles

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Step-by-step explanation:

4 0
3 years ago
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gabriel put 6000 in a 2 year CD paying 4% interest, compounded monthly. After 2 years , he withdrew all his money. what was the
shutvik [7]

amount after 2 years   = 6000(1 + (0.04/12))^24  = 6498.86
7 0
3 years ago
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( 6x ^2 - x + 3 ) +( - 2x + x^2 - 7 )​
alexandr1967 [171]

Answer:

7x² - 3x - 4

Step-by-step explanation:

<u>Step 1: Write expression</u>

(6x² - x + 3) + (-2x + x² - 7)

<u>Step 2: Combine like terms (x²)</u>

7x² - x + 3 - 2x - 7

<u>Step 3: Combine like terms (x)</u>

7x² - 3x + 3 - 7

<u>Step 4: Combine like terms (constants)</u>

7x² - 3x - 4

8 0
3 years ago
33 points | dont guess please | no links
Furkat [3]

Answer:

Joe mama

Step-by-step explanation:

8 0
3 years ago
The three consecutive terms
Studentka2010 [4]

Answer:

<h3>1</h3>

Step-by-step explanation:

The nth term of an exponential sequence is expressed as ar^n-1

The nth term of a linear sequence is expressed as Tn = a + (n-1)d

a is the first term

r is the common ratio

d is the common difference

n is the number of terms

Let the three consecutive terms  of an exponential sequence be a/r, a and ar

second term of a linear sequence = a +d

third term of a linear sequence = a + 2d

sixth term of a linear sequence = a + 5d

Now if the three consecutive terms  of an exponential sequence are  the second third and sixth terms  of a linear sequence, this is expressed as;

a/r = a + d ..... 1

a = a + 2d ..... 2

ar = a+ 5d .... 3

From 2: a = a + 2d

a-a= 2d

0 = 2d

d = 0/2

d = 0

Substitute d = 0 into equation 1:

From 1: a/r = a + d

a/r = a+0

a/r = a

Cross multiply

a = ar

a/a = r

1 = r

Rearrange

r = 1

<em>Hence the common ratio of the exponential sequence is 1</em>

 

 

5 0
3 years ago
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