Question

Which equation in point-slope form contains the points (8, 10) and (–4, 2)?

Answer 1

Answer: Our equation in point-slope form is

$\frac{2x}{3}+\frac{14}{3}$

Explanation:

Since we have given that

there are two points  i.e.

$(8,10)\ and\ (-4,2)$

Equation of point slope form :

$y-y_0=m(x-x_0)\\\\where,\\\\m=\frac{y_2-y_1}{x_2-x_1}$

So, we will first calculate slope of tangent i.e. m

$m=\frac{2-10}{-4-8}\\m=\frac{-8}{-12}\\m=\frac{2}{3}$

So, equation of line in point-slope form is

$(y-10)=\frac{2}{3}(x-8)\\\\3(y-10)=2(x-8)\\\\3y-30=2x-16\\\\3y-2x=-16+30\\\\3y-2x=14\\\\y=\frac{2x}{3}+\frac{14}{3}$

Hence, our equation in point-slope form is

$\frac{2x}{3}+\frac{14}{3}$

Answer 2

Y = 2/3x + 14/3
The slope is from the slope formula and you can substitute points to find b.