<span>Well 68/80 as a percent is 85 % .I got that by dividing 68 by 80 and them multiplying by 100. 100-85= 15. So therefore the dress decreased in price by 15%. </span>
Decimal Form:
4.59375<span>
</span>
Exact Form:
<span>147/32</span><span>
</span>Mixed Number Form: <span>4 19/32</span>
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!