1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
3 years ago
10

The area of a rectangle is 48 cm² and the length of the rectangle is 8 cm longer than the width. The area of a rectangle is foun

d by multiplying the length times the width. During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?
A. w(w+8)=48
B. w + 8 = 48
C. w + 8w = 48
D. 8w = 48
Mathematics
2 answers:
Vitek1552 [10]3 years ago
8 0
I believe the answer is A
andrezito [222]3 years ago
7 0

Answer:

Option A.

Step-by-step explanation:

Let the length of a rectangle is l and width of the rectangle is w,

Then as per statement " Length of the rectangle is 8 cm longer than the width"

l = w + 8

Now we know area of a rectangle is represented by the formula

Area = Length × width

Area = l × w

        = (w + 8)w

Area of the rectangle has been given as 48 cm² then the formula will be

w(w + 8) = 48

Option A is the answer.

You might be interested in
HELP keep saying im getting wrong<br><br>instruction find the perimeter of the polygon​
Ksju [112]

Answer:

perimeter = 50

Step-by-step explanation:

Tangents to a circle from an external point are congruent , then

perimeter = (8 + 8) + (10 + 10) + (7 + 7) = 16 + 20 + 14 = 50

7 0
2 years ago
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.
Damm [24]
The answer:
<span>the two triangles are similar
in addition, the line UV is parallel to line BC, so we can use the theorem of Thales for proving the following ratios:

AV /AC = AU/ AB= UV/ BC
372/589=20x +80  / AB = 444 / 703

</span>so we get    (372/589) AB - 80 =  20x, and x = ( (372/589) AB - 80  ) / 20

exact value of x depends on the value of AB
8 0
3 years ago
A ship leaves port at​ 1:00 pm and travels Upper N 70 degrees Upper WN70°W at the rate of 10 mph. Another ship leaves the same p
Leni [432]

Answer:

30.4 miles

Step-by-step explanations:

Please refer to the attached image for explanations

7 0
3 years ago
Which number should you divide on each side of this equation in order to isolate g? 7g=75+d-12x
xz_007 [3.2K]
Divide both sides by 7
7 0
3 years ago
Write the slope-intercept form (y=mx + b) of the blue line. Explain or show your work. Write a one sentence summary comparing th
Darina [25.2K]

Answer:

y=1/2x+2(2 is the y-intercept)

The blue line and black line have the same y-intercept, but the black line has a slope 1/6 greater than the blue line.

Hope it helps <3

4 0
2 years ago
Read 2 more answers
Other questions:
  • A solid right pyramid has a square base. The length of the base edge is4 cm and the height of the pyramid is 3 cm period what is
    14·1 answer
  • What is the equation for the slope intercept form
    11·1 answer
  • What is the probability of choosing a random license plate who's letter spell out the word"MOM"?
    12·1 answer
  • How many significant figures are there in the following measurement?2.04679 millimeters
    13·1 answer
  • What is the answer when you simplify it?<img src="https://tex.z-dn.net/?f=7%5E%7B2%7D%20%2B2%28%5Csqrt%7B81%7D%20%2B%5Csqrt%7B49
    12·2 answers
  • Which expression is the simplest form of -(4x+y)+2(x-3y)?
    8·1 answer
  • A jewelry box contains two gold hoop earrings and two silver hoop earrings. You randomly choose two earrings. What is the probab
    12·2 answers
  • In a sample of 16 mini-golf balls, 6 are yellow and 10 are pink. If 2 balls are selected at random from the sample, one at a tim
    8·1 answer
  • Solve the formula for m
    6·1 answer
  • You pick a card at random. Without putting the first card back, you pick a second card at random.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!