Ask question

Ask question

All categories

3 years ago

14

What's the difference between an ABSOLUTE extrema and a RELATIVE extrema? ...?

1 answer:

ruslelena [56]3 years ago

3 0

Absolute Extrema<span>. If a function has an </span>absolute<span> maximum at x = b , then f (b) is the largest value that f can attain. Similarly, if a function has an </span>absolute<span> minimum at x = b , then f (b) is the smallest value that f can attain.

</span>The strategy for tracking the sign of the derivative is useful for more than determining where a function is increasing or decreasing. It is also useful for locating the relative extrema of a function. At a relative extrema<span>, a function changes from increasing to decreasing or decreasing to increasing.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

You might be interested in

Subtract (x² + 5x – 6) – (3x^2 – 7x + 1).<br> What is the difference?

Lorico [155]

1. Distribute the Negative Signs
2. Combine like terms
-2x^2 + 12x-7

4 0

3 years ago

What is a theory in science

alina1380 [7]

A scientific theory is a validated explanation of some aspect of the natural world, based on multiple facts that have been frequently verified through research and experimentation. Fact theories are not "guesses" but reliable accounts of the real world.

3 0

3 years ago

Choose a true statement

34kurt

Answer:

A true statement

Step-by-step explanation:

WHAT R THE STATEMENTS

7 0

3 years ago

Read 2 more answers

The oblique pyramid has a square base with an edge length of 5 cm. The height of the pyramid is 7 cm. What is the volume of the

Mandarinka [93]

Answer:

875 cm^3

Step-by-step explanation:

Here, we want to calculate the volume of the pyramid.

To do this, we need to calculate the area of the base and then multiply this by the height of the pyramid in question

Mathematically since the base is a square, formula for the base area would be ;

L^2 = 5^2 = 125 cm ^2

Now

using the height to get the volume , we have 125 * 7 = 875 cm^3

8 0

2 years ago

Read 2 more answers

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago