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Gwar [14]
3 years ago
13

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Mathematics
1 answer:
klasskru [66]3 years ago
6 0
You should put a picture to see what u need help on
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"is it appropriate to use the normal approximation for the sampling distribution of"
Katyanochek1 [597]

Answer: Normal approximation can be used for discrete sampling distributions, such as Binomial distribution and Poisson distribution if certain conditions are met.

Step-by-step explanation: We will give conditions under which the Binomial and Poisson distribitions, which are discrete, can be approximated by the Normal distribution. This procedure is called normal approximation.

1. Binomial distribution: Let the sampling distribution be the binomial distribution B(n,p), where n is the number of trials and p is the probability of success. It can be approximated by the Normal distribution with the mean of np and the variance of np(1-p), denoted by N(np,np(1-p)) if the following condition is met:

n>9\left(\frac{1-p}{p}\right)\text{ and } n>9\left(\frac{p}{1-p}\right)

2. Poisson distribution: Let the sampling distribution be the Poisson distribution P(\lambda) where \lambda is its mean. It can be approximated by the Normal distribution with the mean \lambda and the variance \lambda, denoted by N(\lambda,\lambda) when \lambda is large enough, say \lambda>1000 (however, different sources may give different lower value for \lambda but the greater it is, the better the approximation).

5 0
3 years ago
Which is greater 6/12 or 1/3
Inessa [10]

Answer:

1/3 is bigger

Step-by-step explanation:

6/12 might look bigger but its not

    PLEASE MARK AS BRAINLIEST

5 0
3 years ago
ASAP ILL GOVE 10 POINTS
murzikaleks [220]

Answer:

B

Step-by-step explanation:

Took the test on AP3X

7 0
2 years ago
Read 2 more answers
F(x)=5x-1<br> Domain {-1,0,1,2}<br> Find the range:
Katena32 [7]

Answer:

Step-by-step explanation:

Putting the values in F(x)=5x-1

= -6,-1,5,9

Range =highest -lowest =9--6

=15

3 0
3 years ago
Factor the polynomial.<br> 13x² – 20x – 12
erma4kov [3.2K]

Answer:

(13 x + 6) (x - 2)

Step-by-step explanation:

Factor the following:

13 x^2 - 20 x - 12

Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):

x (13 x + 6) - 2 (13 x + 6)

Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):

Answer: (13 x + 6) (x - 2)

6 0
3 years ago
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