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photoshop1234 [79]
4 years ago
6

Solve the system using substitution.

Mathematics
2 answers:
Lapatulllka [165]4 years ago
5 0

The solution set for the system of linear equations x + y = 8 and y = 3x is \boxed{\left\{{\left({{\mathbf{2,6}}}\right)}\right\}}.

Further explanation:

It is given that the system of linear equations are x + y = 8 and y = 3x.

Consider the given equations as follows:

x + y = 8\,\,\,      ......(1)

y = 3x\,\,\,          ......(2)

From equation (2), the value of y in terms of x is3x.

Now, substitute 3x for y in the equation (1) as follows:

x + 3x = 8

The variable is eliminated in the above equation.

Simplify the equation as follows:

\begin{aligned}x + 3x&=8\\4x&=8\\x&=\frac{8}{4}\\x&=2\\\end{aligned}

Therefore, the value of x is 2.

Substitute 2 for x in the equation (2) and obtain the value of y as shown below.

\begin{aligned}y&= 3\left( 2\right)\\&=6\\\end{aligned}

Therefore, the value of y is 6.

Thus, the ordered pair for the given system of linear equation is \left({{\mathbf{2,6}}} \right).

Check whether the obtained solution (2,6) satisfies the given equations or not.

Substitute 2 for x and 6 for y in the equation (1) and check the equation.

\begin{aligned}2 + 6\mathop&_=^? 8\hfill \\\,\,\,\,\,\,\,8 &= 8\,\,\,\hfill\\\end{aligned}             (True)

The ordered pair \left({2,6}\right) satisfies the equation (1).

Substitute 2 for x and 6 for y in the equation (2) and check the equation.

\begin{aligned}6\mathop&_= ^? \:3\left( 2 \right)\hfill\\6&= 6\,\,\,\,\,\,\,\,\,\,\,\,\hfill\\\end{aligned}              (True)

The ordered pair \left({2,6}\right) satisfies the equation (2).

Thus, the solution set for the system of linear equations x + y = 8 and y = 3x is \boxed{\left\{{\left({{\mathbf{2,6}}}\right)}\right\}}.

Learn more:

1. Which classification best describes the following system of equations? brainly.com/question/9045597

2. Which polynomial is prime?brainly.com/question/1441585

3. Write the subtraction fact two ways 10-3? brainly.com/question/6208262

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Linear equations

Keywords: Substitution, linear equation, system of linear equations in two variables, variables, mathematics,x + y = 8 ,y = 3x , solution set

Alexeev081 [22]4 years ago
4 0

Answer:

Option B that is (2,6) is correct

Explanation:

We have been given with system of equations

X+Y=8 and Y=3X

Here, we will substitute the value of Y=3X in X+Y=8

We will get X+3X=8

Further simplification we will get to 4X=8

Hence, the value of X=2

And now, substituting the value X=2 in Y=3X we will get Y=6.

Therefore, option B is correct.

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Solve x^3-7x^2+7x+15​
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Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

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\underline{\textsf{Find more:}}

Find more:

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