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marta [7]
4 years ago
8

Let ​ f(x)=x2−6x−27 ​ . Enter the x-intercepts of the quadratic function in the boxes. x = and x =

Mathematics
2 answers:
Akimi4 [234]4 years ago
8 0

Answer:

-3, 9

Step-by-step explanation:

x^2 -6x - 27=

= x^2 - 9x + 3x - 27

= x(x - 9) + 3(x - 9)

= (x + 3)(x - 9)

x = -3, x = 9

iren2701 [21]4 years ago
8 0

Answer:

x = 9

x = - 3

Step-by-step explanation:

This factors.

The best way to do this is to start by seeing what answers are possible. Start with 27. What 2 numbers multiply to 27. There aren't many.

27: 1 * 27

27: 3*9                

Now you need the two numbers to add to -6. That means the larger one should be -

The answer is 3 and 9

So the factors are

(x - 9)(x + 3)

x - 9 = 0

x = 9

========

x + 3 = 0

x = - 3

================

The intercepts are the points (9,0) and (-3,0)

x = 9

x = - 3

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Data for a particular subdivision near downtown Houston indicate that the average price per square foot for a home is $100 with
spayn [35]

Answer:

P(X>110)=P(\frac{X-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{5})=P(z>2)

And we can find this probability with the complement rule and we got:

P(Z>2) = 1-P(Z

And using the normal standard table or excel we got:

P(Z>2) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the prices of a population, and for this case we know the distribution for X is given by:

X \sim N(100,5)  

Where \mu=100 and \sigma=5

We are interested on this probability

P(X>110)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>110)=P(\frac{X-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{5})=P(z>2)

And we can find this probability with the complement rule and we got:

P(Z>2) = 1-P(Z

And using the normal standard table or excel we got:

P(Z>2) = 1-P(Z

And we can find this probability on this way:

P(-0.50

6 0
3 years ago
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