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maria [59]
3 years ago
9

Shopping the price of a pound of cook shrimp was $3.29. how much was this to the nearest dollar?

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0
Are you just rounding to the nearest dollar isf so its 3.00 because the number next to 3 has to higher then 5 to be 4.00
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5x +1 = -3+10x how do you solve this
Natali5045456 [20]

Answer:

x = 4/5

Step-by-step explanation:

Group like terms together.  Start by subtracting 1 from both sides, obtaining

5x = -4 + 10x.

Then combine the x terms, obtaining 4 = 5x.

Solving for x by dividing both sides by 5, we get x = 4/5.

7 0
3 years ago
Read 2 more answers
It's question B as I've done A please help
Hatshy [7]
Its easy.use cos rule.
4 0
3 years ago
The last rest area you spent $3.25 on water bottles, $11.00 on snacks, and $4.00 on a magazine, and gave the cashier $20.00 How
photoshop1234 [79]

Answer:

You spent 18.25, and got 1.75 in change

Step-by-step explanation:

3.25 + 11 + 4 = 18.25

20.00 - 18.25 = 1.75

6 0
3 years ago
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La barbería El Caleño, tiene en promedio 120 clientes a la semana a
Luba_88 [7]

Queremos maximizar el precio de tal forma que los ingresos no disminuyan.

Ese maximo precio es: $14,040.6

Sabemos que actualmente el precio es:

p = $6,000

El número de clientes es:

C = 120

Actualmente los ingresos son el producto de esos dos números, es decir:

ingresos = $6,000*120 = $720,000

Ahora sabemos que por cada incremento de $700 en el precio, el número de clientes decrece en 10.

Entonces podemos escribir el número de clientes como una ecuación lineal.

C(p) = a*p + b

tal que tenemos dos puntos en esa linea:

($6,000, 120)

($6,700, 110)

La pendiente es:

a = \frac{110 - 120}{\$6,700 - \$6,000} = \frac{-10}{\$ 700}

Entonces tenemos:

C(p) = (-10/$700)*p + b

Sabemos que:

C($6,000) = 120 = (-10/$700)*$6,000 + b

                     120 = -85.71 + b

                     120 + 85.71 = b =

Entonces la ecuación lineal es:

C(p) = (-10/$700)*p + 205.71

Los ingresos serán dados por:

ingresos = C(p)*p = (-10/$700)*p^2 + 205.71*p

Y queremos maximizar p de tal forma que esto sea igual a lo que obtuvimos antes:

(-10/$700)*p^2 + 205.71*p = $720,000

Entonces debemos resolver la ecuación cuadratica:

(-10/$700)*p^2 + 205.71*p - $720,000 = 0.

Las soluciones son dadas por la formula de Bhaskara.

p = \frac{-205.71 \pm \sqrt{(205.71)^2 - 4*(-10/\$ 700)*\$ 720,000} }{2*(-10/\$ 700)} \\\\p = \frac{-205.71 \pm 195.45}{(-20/\$ 700)}

La solución de maximo valor es:

p = (-205.71 - 195.45)/(-20/$700) = $14,040.6

Sí quieres aprender más, puedes leer.

brainly.com/question/8926135

7 0
3 years ago
Can someone please explain how to divide fractions?
Natasha2012 [34]
Keep the first fraction
Switch the division to multiplication
Flip the numbers on the second fraction
5 0
3 years ago
Read 2 more answers
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