Simply add up all.
4 1/2 + 6 2/3 + 9 1/4
(4 + 6 + 9) + 1/2 + 2/3 + 1/4
19 6/12 + 8/12 + 3/12 = (6+8+3)/12 = 17/12
19 17/12
19 1 5/12
19 + 1 5/12
= 20 5/12
20 5/12 yards was purchased.
1/2 is the probability, or 50%. There are 4 teams of S and B n the Y, 2 are B. so its 2/4
Answer:
16/100 = 4/25
Step-by-step explanation:
4/10 * 4/10 = 16/100
Answer:
Option C
Step-by-step explanation:
We are given a coefficient matrix along and not the solution matrix
Since solution matrix is not given we cannot check for infinity solutions.
But we can check whether coefficient matrix is 0 or not
If coefficient matrix is zero, the system is inconsistent and hence no solution.
Option A)
|A|=![\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%266%5C%5C2%261%263%5C%5C-2%263%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D0)
since II row is a multiple of I row
Hence no solution or infinite
OPtion B
|B|=![\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%260%26-2%5C%5C-7%261%265%5C%5C4%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
Hence no solution or infinite
Option C
![\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%260%26-2%5C%5C-2%260%266%5C%5C1%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2836-2%29%3D68)
Hence there will be a unique solution
Option D
=0
(since I row is -5 times III row)
Hence there will be no or infinite solution
Option C is the correct answer
Answer: 10 verticesTo make a full circle(360 °), the number of 40° lines you need will be: 360/40=9 lines. So, the base of the pyramid would be made of 9 lines.Pyramid has a base and sides. The sides number is equal to the number of lines of the base. Then, the number of faces/vertices would be: 1 + 9= 10
If the question saying literally 40 edges(not degrees), then the pyramid base would be 40 lines. In this case, the number of vertices would be: 1+40=41