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AlladinOne [14]
3 years ago
6

You can make groups of 3, 4, or 9 pencils with none left over. What is smallest number of pencils you must have to make these gr

oups?

Mathematics
1 answer:
swat323 years ago
4 0

Answer:

=36

Step-by-step explanation:

Step-by-step explanation:

for this we has to take the LCM of 3,4 and 9 to find the least common factor in between these three numbers.....

so we have to multiply 3×3×4

=36

so if we divide 36 by 3 ,4 OR 9

we will not find any remainder

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Aljan and Bella are both driving from Cleveland to Chicago. Aljan leaves at
Natalija [7]

Answer:

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

Step-by-step explanation:

In order to calculate the number of hours, "x", that it'll take for Bella to pass Aljan, we need to find the value of "x" that makes both equations equal. Therefore,

60*x + 20 = 65*x\\65*x - 60*x = 20\\5*x = 20\\x = \frac{20}{5} = 4

In order to calculate the distance they traveled, we must use this value for "x" in any of the equations, as done below:

y = 65*4\\y = 260

Bella will pass Ajjan after 4h and they will have travelled 260 miles.

4 0
3 years ago
100 POINTS!!!!!! HELP
irga5000 [103]
A - 1766! I hope this helps
7 0
3 years ago
......:.. ....... ....
Fynjy0 [20]
84 degrees

The triangle is isosceles you know this from the 2 congruent sides marked 5

Thus angle F is 48 degrees

To find angle E-
180 - (48 + 48) = 84
4 0
3 years ago
Read 2 more answers
PLEASE HELP!!
kirza4 [7]

Answer:

Each line segment joining a vertex of ABCD to the corresponding vertex in the image is perpendicular to the line of reflection, EF. That is, the lines intersect at a 90 degree angle.

3 0
3 years ago
A rocket is launched from the top of a 55-foot cliff with an initial velocity of 138 ft/s.
melisa1 [442]

For this case we have that the equation that describes the height is:

h = -16t ^ 2 + vt + c

Where,

v: initial speed

c: initial height

Substituting values we have:

h = -16t ^ 2 + 138t + 55

Then, to find the time, we use the quadratic formula:

t =\frac{-b +/-\sqrt{b^2 - 4ac} }{2a}

Substituting values we have:

t =\frac{-138 +/-\sqrt{138^2 - 4(-16)(55)} }{2(-16)}

Rewriting:

t =\frac{-138 +/-\sqrt{19044 + 3520} }{-32}

t =\frac{-138 +/-\sqrt{22564}}{-32}

t =\frac{-138 +/-150.21}{-32}

We discard the negative root because we want to find the time.

We have then:

t =\frac{-138 -150.21}{-32}

t =\frac{-288.21}{-32}   \\t=9

Answer:

D. 0 = -16t^2 + 138t + 55; 9 s

3 0
3 years ago
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