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olga nikolaevna [1]
3 years ago
14

Write the phrase as an expression. Then evaluate when y=20 . 3 less than the quotient of a number y and 4

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Expression: <span>y÷4−3</span>

When <span><span>y=20</span><span>y=20</span></span>, the value of the expression is 2.

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Answer: Order the data to find the minimum, maximum, and quartiles.

206, 374, 421, 469, 489, 505, 531, 573, 702.

Step-by-step explanation: I hoped this helped in some way or form.

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What is the measure of z?<br> an<br> z= [?
Gemiola [76]

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Fernando bought a jacket for 185 and sold it for 1 1/2 what he paid. Marisol spent 1/5 as much as Fernando on the same jacket bu
avanturin [10]

Answer:

Marisol made $138.75 on the sale of the jacket

Step-by-step explanation:

First we are told that Fernando bought a jacket for $185, and sold it for 1 1/12 what he paid.

Therefore, 1 1/2 of 185;

= 1.5 × 185 = $277.5

Therefore, Fernando sold the Jacket for $277.5

Next, we are told that:

Marisol spent 1/5 as much as Fernando on the same jacket

This means that Marisol spent 1/5 of $185 on the jacket

= 1/5 × 185 = 0.2 × 185 = $37

Therefore, Marisol spent $37 to buy the same jacket

Next, Marisol sold the jacket for 1/2 as much as Fernando. Since Fernando sold the Jacket for $277.5, Marisol sold the jacket for 1/2 of 277.5, and this is calculated as:

1/2 of 277.5 = 0.5 × 277.5 = 138.75

Therefore, Marisol made $138.75 on the sale of the jacket.

6 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
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