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3 years ago

What is the distance between (8, -3) and (4, -7)?

Mathematics

1 answer:

lesantik [10]3 years ago

6 0

Answer:

d=4√2

Step-by-step explanation:

distance formula = √(x2-x1)²+(y2-y1)²

d=√(4-8)²+(-7-(-3))²

d=√4²+(-4)²

d=√16+16 = √32=√2²*2²*2

d=4√2

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Which number can each term of the equation be multiplied by to eliminate the fractions before solving ?

Zolol [24]

Answer:

Step-by-step explanation:

-3/4m - 1/2 = 2 + 1/4m

The denominators are 4 and 2

If we multiply by the least common multiply we can get rid of the fractions

2 and 4 have a least common multiple of 4

5 0

3 years ago

Isaac keeps track of the miles per gallon his car gets per week. He has accumulated the following data:

ipn [44]

we know that

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant

Let

$a1=24 \ a2=24.48\ a3=24.97\ a4=25.47$

$\frac{a2}{a1} = \frac{24.48}{24}= 1.02$

$a2=a1*1.02$

$\frac{a3}{a2} = \frac{24.97}{24.48}= 1.02$

$a3=a2*1.02$

$\frac{a4}{a3} = \frac{25.47}{24.97}= 1.02$

$a4=a3*1.02$

therefore

The common ratio is equal to $1.02$

the answer is

The common ratio is 1.02

4 0

3 years ago

Read 2 more answers

Solve for a. 5a - 2 = 23 a = ?

snow_tiger [21]

5a - 2 = 23.

First, take 5a - 2 = 23 and add 2 to each side

5a - 2 = 23
+2 +2
5a = 25

now, divide each side by 5

5a = 25
/5 /5

a = 5

3 0

2 years ago

Read 2 more answers

How many 4 card hands that contain exactly 3 aces and 1 queen can be chosen from a 52 card deck?

sesenic [268]

There are 16 possible hands.

Choosing 3 aces from 4 possible is expressed by:
$_4C_3=\frac{4!}{3!1!} = 4$

Choosing 1 queen from 4 possible is expressed by:
$_4C_1=\frac{4!}{1!3!}=4$

This gives us 4*4 = 16 possible hands.

7 0

3 years ago

Find the rate change

Goshia [24]

Rate change is $3.50

4 0

2 years ago