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valkas [14]
3 years ago
9

Help im desperatrte pls

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

337.5

Step-by-step explanation:

4 1/2*5*3 3/4

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What is the ordered pair or real numbers for which x + y = 99 and x^2 - y^2 = 99.
skad [1K]

Given : x + y = 99 ------------ [1]

Given : x² - y² = 99

We know that : (x² - y²) = (x + y)(x - y)

⇒ (x + y)(x - y) = 99

⇒ 99(x - y) = 99

⇒ x - y = 1 ------------- [2]

Adding Equation [1] and [2], we get :

⇒ (x + y) + (x - y) = 99 + 1

⇒ 2x = 100

⇒ x = 50

Substituting x = 50 in Equation [1], we get :

⇒ 50 + y = 99

⇒ y = 99 - 50

⇒ y = 49

So, The Ordered pair (x , y) = (50 , 49)

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3 years ago
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SVETLANKA909090 [29]
\frac { 3 }{ 4 } 's \frac { 1 }{ 2 } is equal to :

\frac { 3 }{ 4 } \cdot \frac { 1 }{ 2 } =\frac { 3\cdot 1 }{ 4\cdot 2 } =\frac { 3 }{ 8 }
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3 years ago
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