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dalvyx [7]
3 years ago
9

Frank has 24 pennies, 62 nickels, 55 dimes, 16 quarters, and 19 fifty-cent pieces. How much money does he have?

Mathematics
1 answer:
erik [133]3 years ago
5 0

Answer:

$22.34

Step-by-step explanation:

24 pennies is .24 of a dollar

62 nickels will be: (62 x 5) / 100 = 3.10

55 dimes is 5.5

16 quarters will be 4.0

19 fifty-cents will be 9.5

Add them up to get $22.34 if I’m right.

Hope this helped.

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poizon [28]
The answer is 2 y= 2 so 3•2=6 6-4=2
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An organization has members who possess IQs in the top 4% of the population. If IQs are normally distributed, with a mean of 100
murzikaleks [220]

Answer:

The minimum IQ score will be "126".

Step-by-step explanation:

The given values are:

Mean

\mu = 100

Standard deviation

\sigma=15

Now,

⇒ P(z>x)=4 \ percent \ i.e., 0.04

⇒ P(z>\frac{x- \mu}{\sigma} )=0.04

⇒ 1-P(z \leq \frac{x-100}{15})=0.04

⇒ \frac{x-100}{15}=z0.96

            =NORMDIS(z=0.96)

            =1.751

⇒ x=100+15\times 1.751

      =126.265 \ i.e., 126

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3 years ago
The price of a gallon of unleaded gas was $2.83 yesterday. Today, the price fell to $2.78 . Find the percentage decrease. Round
avanturin [10]
2.105% is the answer!
8 0
3 years ago
LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)
klasskru [66]

\huge \bf༆ Answer ༄

Let's solve ~

\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }

\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times   3{k}^{4} }

\qquad \looparrowright \sf - 2 \times 2 {}^{3}  \times  {k}^{2}   \times \sqrt{3}

\qquad \looparrowright \sf  - 16 {k}^{2}  \sqrt{3}

Hence, the correct choice is D

5 0
2 years ago
Read 2 more answers
The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.
lorasvet [3.4K]
p = 2w + 2l              p = 42 
a = l * w                   a = 108

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2 
               2's  cancel  out
\frac{p}{2} = w + l

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
\frac{p}{2} - l = w + l - l
                 l's  cancel  out 
p/2 - l = w

a = l * w

You replace w with the equation above p/2 - l = w 
a = l( \frac{p}{2} - l)

Multiply out the L.
a = \frac{p}{2}l - l^{2}

Plug in all your numbers a = 110 and p = 42
110 = \frac{42}{2}l - l^{2}
110 = 21l - l^{2

Move everything to the left side so l^{2} would be positive (makes the equation easier when l^{2} is positive).
l^{2} - 21l + 110 = 0

Factor.
(l -10)(l-11) = 0

Make each parenthesis set equal to 0.
l-11=0     l-10=0

Add.
l = 11  l = 10

By doing this you solve for both the width and length so the answer is:
w = 11    L = 10
8 0
3 years ago
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