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lina2011 [118]
3 years ago
6

Please help this is hard

Mathematics
1 answer:
olganol [36]3 years ago
7 0
'Consider the formula for the slope between two coordinate points; m, shown below.

m = y2 - y1/x2 - x1

Which of the following equations is equivalent to the slope formula?'


I think it would be C
You might be interested in
The equation of the hyperbola with center at (0, 0) opening horizontally, with a = 2, b = 5 is:
tresset_1 [31]

Answer:

\frac{x^2}{4}-\frac{y^2}{25} =1

Step-by-step explanation:

we are given

center =(0,0)

we can compare with

center=(h,k)=(0,0)

so, h=0 and k=0

a=2 and b=5

now, we can use equation of hyperbola formula

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1

now, we can plug values

\frac{(x-0)^2}{2^2}-\frac{(y-0)^2}{5^2} =1

we can simplify it

and we get equation of hyperbola as

\frac{x^2}{4}-\frac{y^2}{25} =1


5 0
3 years ago
Consider the following dot plots.
MrRa [10]
The statement that is true is that the median pitches are 5 apart.

10,15,15,15,15,20,20,25,25
Median:15 is in the middle

10,15,15,15,20,25,25,25,25
Median: 20 is in the middle



7 0
3 years ago
Plz solve for brain thing.<br> surry. im new
luda_lava [24]

Answer:

1. 1/4 because rectangle B takes up 1/2 of the space and the two triangles together take up 1/4.

2. 1/2, because it is twice as big as C, which takes up 1/4 of the space.

3. 1/8, because both A and D together take up 1/4 of the space, and they are both the same size

4. 1/3, because the triangles around it each take up 1/6 of the space

5. 1/6, because it is half as large as square J, which takes up 1/3 of the space

Step-by-step explanation:

(hope this helps!)

4 0
3 years ago
Find the quation of the quadratic function with roots 0 and 4 and a vertex at (2,-2)
Nookie1986 [14]

Answer:

y = (1/2)x² -2x

Step-by-step explanation:

recall that the general equation of a quadratic function is:

y = Ax² + Bx + C

given that 0 and 4 are roots, that means when x = 0 and x = 4, then  y = 0

From this we can get 2 points on the curve, namely,  (0,0) and (4,0)

substituting these points one at a time into the equation above,

for the first point (0,0),

0 = A (0)² + b(0) + C

C = 0

hence the equation becomes:    y = Ax² + Bx

for the 2nd known point (4,0)

0 = A(4)² + B(4)

0 = 16A + 4B   (divide both sides by 4)

0 = 4A + B

B = -4A    ------------(eq 1)

we are given a 3rd point, vertex at (2,-2)

for (2,-2)

-2 = A(2²) + B(2)

-2 = 4A + 2B   (divide both sides by 2)

-1 = 2A + B   (subtract 2A from both sides)

B = -1 -2A --------(eq 2)

solving the system of equations using the method of your choice in eq1 and eq 2 gives:

A = 1/2 and B = -2

hence the equation is

y = (1/2)x² -2x

7 0
3 years ago
What is the domain of the function ya v?<br> O 0 O 0 O 1
umka21 [38]

Answer:

C

Step-by-step explanation:

X can't be negative cause it wouldn't make sense

8 0
3 years ago
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