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4 years ago

Solve the following system of equations using the elimination method. 2x + 4y = 10 –2x + y = –15

Mathematics

2 answers:

Vera_Pavlovna [14]4 years ago

8 0

(7, - 1 )

Step-by-step explanation:

Given the 2 equations

2x + 4y = 10 → (1)

- 2x + y = - 15 → (2)

Adding the 2 equations term by term eliminates the term in x, that is

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into either of the 2 equations and solve for x

Substituting into (1)

2x + 4(- 1) = 10

2x - 4 = 10 ( add 4 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

Solution is (7, - 1 )

pychu [463]4 years ago

6 0

Answer:

(7, - 1 )

Step-by-step explanation:

Given the 2 equations

2x + 4y = 10 → (1)

- 2x + y = - 15 → (2)

Adding the 2 equations term by term eliminates the term in x, that is

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into either of the 2 equations and solve for x

Substituting into (1)

2x + 4(- 1) = 10

2x - 4 = 10 ( add 4 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

Solution is (7, - 1 )

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3 years ago

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Which statement best explains the relationship between lines PQ and RS? They are parallel because their slopes are equal. They a

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Answer:

They are not parallel because their slopes are not equal

Step-by-step explanation:

From the diagram attached, The line PQ has point P at (-5, 3) and point Q at (5, 1).

For line RS, point R is at (-4, -2) and point S is at (0, -4).

Two lines AB and CD are said to be parallel to each other if they have the same slope, i.e if the slope of AB is m1 and the slope of CD is m2, m1 = m2. When two lines are parallel, they can never intersect.

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$m=\frac{y_2-y_1}{x_2-x_1}$

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For line RS, point R is at (-4, -2) and point S is at (0, -4), the slope is given as:

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