Find the area of the smaller sector.

Mathematics

2 answers:

almond37 [142]1 year ago

6 0

Answer: 22.2 ft^2

Step-by-Step Solution:

Radius (r) = 7.13 ft
Angle (θ) = 50°

Area of a Sector = θ/360 * πr^2

Therefore,
= θ/360 * πr^2
= θ/360 * π * r * r
= 50/360 * 3.14 * 7.13 * 7.13
= 50/360 * 3.14 * 50.8369
= 5/36 * 159.63
= 798.15/36
= 22.17
=> 22.2

Area of the Sector = 22.2 ft^2

sveticcg [70]1 year ago

3 0

Answer:

A ≈ 22.2 ft²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

= πr² × $\frac{50}{360}$

= π × 7.13² × $\frac{5}{36}$

= 50.8369π × $\frac{5}{36}$

≈ 22.2 ft² ( to the nearest tenth )

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Find the area of the shaded segment of the circle.

vredina [299]

Answer:

Around 5.5 square meters

Step-by-step explanation:

You can start by finding the area of the segment. Since the rest of the circle that is not in the segment is 240 degrees, the segment is 120 degrees or a third of the circle. You can therefore find the area of that segment with the formula $\frac{1}{3} \pi r^2 =3\pi$ square meters. Now, you need to find the area of the triangle inside the sector. This is more difficult than last time, because it is not a 90 degree angle. However, you can solve this by dividing this triangle into two 30-60-90 triangles, which you know how to find the ratio of sides for. In a 30-60-90 triangle, the hypotenuse is twice the length of the smallest leg, and the larger leg is $\sqrt{3}$ times larger than the smaller leg. In this case, these dimensions are a base of $\frac{3}{2}$ for the smaller leg and $\frac{3\sqrt{3}}{2}$ for the larger leg, or the base. Using the triangle area formula and multiplying by 2 (because remember, we divided the big triangle in half), you get $\frac{9\sqrt{3}}{4}$ square meters. Subtracting this from the area of the segment, you get about 5.5 square meters. Hope this helps!