Question

What is an equation of the line that contains the point (3,-1) and is perpendicular to the line whose equation is y=-3x+2

Answer 1

Answer:

Equation of the line: $3y=x+10$

Step-by-step explanation:

If an equation of a line is perpendicular, its gradient will be such that: $m_1 \times m_2 = -1$

Since the gradient /slope of the given equation can be inferred as -3, the gradient of the perpendicular line will be $\frac{1}{3}$.

Coordinates of a point on the line are (3,-1)

$(y-y_1) = m(x-x_1)\\\\(y-3) = \frac{1}{3} (x+1)\\\\3(y-3) = (x+1)\\3y -9= x+1\\3y = x+1+9\\3y = x+10$