Answer:
-12p^7q^9
Step-by-step explanation:
(-2/3Pq^4)^2×(-27P^5q)
= ((-2)^2)/3^2 × P^2 q^4-2 × (-27qp^5)
= ((-2)^2)/3^2 × 27p^7q9
= (((-2)^2 x 27p^7q9)/3^2
= -((4×27p^7q^9)/9)
= -(108p^7q^9)/9
= -12p^7q^9
The lowest common multiple of 12 and 27 is 108.
12 x 9 = 108 and
27 x 4 = 108 .
So she has to buy 9 packs of cards ... 108 of them ... and 4 packs of envelopes.
Answer: Yes, because there are at least two claims
Step-by-step explanation:
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