Given:
Polynomials
To find:
Monomial of 2nd degree with leading coefficient 3
Solution:
Monomial is an algebraic expression with only one term.
Option A: ![3 n^{2}-1](https://tex.z-dn.net/?f=3%20n%5E%7B2%7D-1)
It is not a monomial because it have 2 terms.
It is not true.
Option B:
It is not a monomial because it have 2 terms.
It is not true.
Option C: ![3 n^{2}](https://tex.z-dn.net/?f=3%20n%5E%7B2%7D)
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 2
Leading coefficient means the value before variable.
Leading coefficient = 3
It is true.
Option D: ![2n^3](https://tex.z-dn.net/?f=2n%5E3)
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 3
It is not true.
Therefore
is a monomial of 2nd degree with a leading coefficient of 3.
The answer to this question is:
280ft^2 for surface area
The volume is 300ft^2
4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
Answer:
26%
Step-by-step explanation:
Subtract the old amt from the new amt, then divide by the old amt:
19-15/15 = 4/15 = 26.6%. Rounded to the nearest tenth it would be 26%.
please give me the brainliest.