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3 years ago

What is (x^4)/(x^0)?

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Answer:

$\frac{x^{4}}{x^{0}}=\frac{x^{4}}{1}=x^{4}$

Step-by-step explanation:

$any~number~to~the~power~of~0~equal~to~1$

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Your class is selling boxes of flowers as a fundraiser. The profit p depends on the amount x that your class charges for each bo

Korvikt [17]

Answer:

$ 22.6

Step-by-step explanation:

Given that

Price charged for each box of seeds = x

Profit gained from from selling boxes of seeds = p

The equation of profit is modeled as

P(x) = 0.5x² + 36x - 179

As per given information if the fundraisers make a profit of $379 then find the minimum price charged for each box of seed.

Now our above equation becomes

379 = -0.5x² + 36x - 179

Simplifying

379+179 = -0.5x² + 36x

558 = -0.5x² + 36x

0.5x² - 36x + 558 =0

multipying both sides of equation by 2

2(0.5x² - 36x + 558) = 2x0

x² - 72x +1116 = 0

Using quadratic formula we get the following factors

x= 49.4 or x= 22.60

As we can the smalles value is 22.6

So, they can charge 22.6 dollar for each bag of seeds in order to get profit of 379 dollars.

NOTE.- just substitute values and resolve

5 0

4 years ago

Now examine |a + bi| and complete the definition below. The absolute value of any complex number a + bi is the from (a, b) to (0

sergejj [24]

Distance

|a+bi| is the length of the vector from origin to (a,b).

$|a+bi| = \sqrt{a^2 + b^2}$

8 0

4 years ago

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If $6,000 is placed in an account with an annual interest rate of 6%, how long will it take the amount to triple if the interest

Dennis_Churaev [7]

3p=p(1+0.06)^t
3=(1.06)^t
T=log(3)÷log(1.06)
T=18.9 years

4 0

3 years ago

Find the sum of the geometric series. a b c d

Musya8 [376]

Answer:

B. $4\sqrt{3}-6$

Step-by-step explanation:

We have,

The first term of the series, $a=\sqrt{3}$ .

The common difference is given by, $r=\frac{\frac{-3}{2}}{\sqrt{3}}$ i.e. $r=\frac{-\sqrt{3}}{2}$ .

Since, the given series is an infinite series, then,

Sum of an infinite series = $\frac{a}{1-r}$

i.e. Sum the series = $\frac{\sqrt{3}}{1+\frac{\sqrt{3}}{2}}$

i.e. Sum the series = $\frac{2\sqrt{3}}{2+\sqrt{3}}$

i.e. Sum the series = $\frac{2\sqrt{3}}{2+\sqrt{3}}\times \frac{2-\sqrt{3}}{2-\sqrt{3}}$

i.e. Sum the series = $\frac{2\sqrt{3}\times (2-\sqrt{3})}{4-3}$

i.e. Sum the series = $4\sqrt{3}-6$

Thus, the sum of the series is $4\sqrt{3}-6$ .

8 0

3 years ago

Helppp!! 21 - 3y = -18 3x+ y = -5

Ugo [173]

Answer:

(-3,4)

Step-by-step explanation:

A system of equations is given to us. The given equations are ,

$\implies 2x - 3y = -18$

$\implies 3x + y =-5$

We need to plot the graph and find the solution of the given system . For that refer to attachment . The point at which both the lines of the graph will intersect each other will be the solution of the given system of equations .

From the graph we can see that it intersect at (-3,4) . Therefore the Solution is ,

$\longrightarrow \underline{\underline{ Solution = (-3,4)}}$

8 0

3 years ago

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