Answer:
B. medium of exchange.
Explanation:
Money as a medium of exchange is used to facilitate the selling and purchasing of goods and services between parties. Money is widely accepted as a standard of value by parties engaged in the exchange of commodities. It means that one party readily accepts an amount of money in exchange for a product or service that is believed to be worth the amount on offer.
Tara is exchanging her $50,000 for the house. Although the money is only a down-payment, it gives her the right to claim ownership of the house. Once she has fully paid for the house using money, she can only lay a claim on the house, not the money.
Answer:
Only final goods and services are included in the calculation of GDP to avoid counting things multiple times.
Explanation:
In the calculation of the GDP only final goods and services are included because the prices of the these already have the costs of all the things that were used to produce them. If we count the intermediate products and services that were used for the final output, we will be double counting which will give a result that is not a correct estimation.
Excluded services are those services which health insurance companies do not pay for. Those services may be needed or necessary but they are not covered by the health insurance plan and the person concerned will have to pay for the service himself. Services that are not reasonable or necessary refer to those services which are not deem necessary in the treatment of a patient.
Answer:
the budgeted selling and administrative expenses for July is $64,100
Explanation:
The computation of the budgeted selling and administrative expenses for July is shown below:
= Budgeted selling & admin cost + (per unit sold × July units)
= $20,000 + ($9 × 4,900 units)
= $20,000 + $44,100
= $64,100
hence, the budgeted selling and administrative expenses for July is $64,100
We simply applied the above formula
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
