If 5.7 moles of zinc metal react with 8.9 moles of silver nitrate, how many moles of silver metal can be formed, and how many mo
les of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Zn + AgNO3 → Zn(NO3)2 + Ag Be sure to show all of your work.
<span>the ratio between Zn and AgNO3 is 1 : 2 </span>
<span>moles AgNO3 required = 5.7 x 2 =11.4 </span>
<span>we have only 8.9 moles of AgNO3 so it is the limiting reactant </span>
<span>moles Zn needed = 8.9/2=4.45 </span>
<span>moles Zn in excess = 5.7 - 4.45 =1.25 ( or 1.3 at two significant figures)
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