If 5.7 moles of zinc metal react with 8.9 moles of silver nitrate, how many moles of silver metal can be formed, and how many mo
les of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Zn + AgNO3 → Zn(NO3)2 + Ag Be sure to show all of your work.
<span>the ratio between Zn and AgNO3 is 1 : 2 </span>
<span>moles AgNO3 required = 5.7 x 2 =11.4 </span>
<span>we have only 8.9 moles of AgNO3 so it is the limiting reactant </span>
<span>moles Zn needed = 8.9/2=4.45 </span>
<span>moles Zn in excess = 5.7 - 4.45 =1.25 ( or 1.3 at two significant figures)
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Remember that percent means parts out of 100 x/100
discount is the decrease so we divide the decrease by the original total and get 100/5775=0.0173 convert to fraction 0.0173/1 make bottom number 100 multiply by 100/100 1.73/100=1.73% round 2%