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igor_vitrenko [27]
3 years ago
12

If 5.7 moles of zinc metal react with 8.9 moles of silver nitrate, how many moles of silver metal can be formed, and how many mo

les of the excess reactant will be left over when the reaction is complete? Unbalanced equation: Zn + AgNO3 → Zn(NO3)2 + Ag Be sure to show all of your work.
Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
The balanced equation is 

<span>Zn + 2 AgNO3 = Zn(NO3)2 + 2 Ag </span>

<span>the ratio between Zn and AgNO3 is 1 : 2 </span>

<span>moles AgNO3 required = 5.7 x 2 =11.4 </span>

<span>we have only 8.9 moles of AgNO3 so it is the limiting reactant </span>

<span>moles Zn needed = 8.9/2=4.45 </span>

<span>moles Zn in excess = 5.7 - 4.45 =1.25 ( or 1.3 at two significant figures)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

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Subtract 130.35 from both sides.

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Divide both sides by -0.29.

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____________________________________________________________

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____________________________________________________________

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____________________________________________________________

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____________________________________________________________

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Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

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