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3 years ago

The graphs of y=x2- 3 and y = 3x -4 intersect at

Mathematics

1 answer:

OLga [1]3 years ago

8 0

Answer:

Option 3) (0.38, -2.85) and (2.62,3.85)

Step-by-step explanation:

we have

$y=x^{2}-3$ ----> equation A

$y=3x-4$ ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The intersection points are (0.38,-2.85) and (2.62,3.85)

see the attached figure

therefore

The graphs intersect approximately at (0.38,-2.85) and (2.62,3.85)

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Answer:

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Step-by-step explanation:

Divide 75 by 30 to get 2

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Step-by-step explanation:

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2 years ago

How many solutions does this linear system have y= 1/2x+4 <br> x+2y=-8

lara [203]

Answer:

1 solution

Step-by-step explanation:

y = 1/2x + 4

x + 2y = -8

Solve the second equation for y.

2y = -x - 8

y = -1/2x - 4

The two equations in slope-intercept form are:

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2 years ago

Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th

HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

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3 years ago