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Shalnov [3]
3 years ago
14

The graphs of y=x2- 3 and y = 3x -4 intersect at

Mathematics
1 answer:
OLga [1]3 years ago
8 0

Answer:

Option 3) (0.38, -2.85) and (2.62,3.85)

Step-by-step explanation:

we have

y=x^{2}-3 ----> equation A

y=3x-4 ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The intersection points are (0.38,-2.85) and (2.62,3.85)

see the attached figure

therefore

The graphs intersect approximately at (0.38,-2.85) and (2.62,3.85)

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What is 30 divided by 75 and show the work plz?
lions [1.4K]

Answer:

75/30= 2 with a remainder of 15

Step-by-step explanation:

Divide 75 by 30 to get 2

Multiply the quotient digit (2) by the divisor 30

subtract 60 from 75

the solution for long division of 75/ 30 is 2 remainder of 15

convert it to mixed number

2 15/30

4 0
3 years ago
How do you do this ??????????????????????
kicyunya [14]

Answer:

b

Step-by-step explanation:

you can take the rectagel and you x the rectagel

6 0
3 years ago
A price is decreased by 24% and is now £372.40.<br>Work out the original price.​
goldfiish [28.3K]

Answer:

Step-by-step explanation:

Subtract the discount from 100 to get the percentage of the original price.

Multiply the final price by 100.

Divide by the percentage in Step One

5 0
2 years ago
How many solutions does this linear system have y= 1/2x+4 <br> x+2y=-8
lara [203]

Answer:

1 solution

Step-by-step explanation:

y = 1/2x + 4  

x + 2y = -8

Solve the second equation for y.

2y = -x - 8

y = -1/2x - 4

The two equations in slope-intercept form are:

y = 1/2x + 4

y = -1/2x - 4

The system consists of two lines with different slopes, so they intercept at a single point which is the solution.

Answer: 1 solution

4 0
2 years ago
Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th
HACTEHA [7]

Answer:

Required equation of tangent plane is z=\frac{6}{5}(x-5y-11).

Step-by-step explanation:

Given surface function is,

f(x,y)=6-\frac{6}{5}(x-y)

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)

So that,

f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}

f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}

f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6

Substitute all these values in (1) we get,

z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}

\therefore z=\frac{6}{5}(x-5y-11)

Which is the required euation of tangent plane.

4 0
3 years ago
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