Here is the solution based on the given situation above.
Given: 450 kg = weight limit of the elevator
750 kg = current weight of the group of passengers
? = number of passengers who weigh 70 kgs that need to get off the elevator
So to get the answer, first we need to deduct 450kg from 750 kgs to get the excess weight. So 750 - 450 is 300kgs. Next, we divide 300 by 70kgs to get the number of passengers that need to get off so 300/70 is 4.3. Therefore, there should be 4 passengers who weigh 70 kilograms that need to get off the elevator.
Answer:
The answer is 7.2368421053 .
Answer:
Decimal - 0.19 Fraction - 19/100
Step-by-step explanation:
Answer:
here is your answer........
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
