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anyanavicka [17]
3 years ago
10

Do these questions please

Mathematics
2 answers:
ddd [48]3 years ago
7 0

Answer:

1.) B

2.) F

3.) D

4.) I think it is J

Step-by-step explanation:

djyliett [7]3 years ago
5 0

Answer:1.b,3.d,2.f,4.h

Step-by-step explanation:

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435 is 15% of what number?
melamori03 [73]
435 is 15% of 2900 that is the answer
7 0
4 years ago
Vedant runs around a square park of side 42m, three times. Rehan runs around a rectangular park of length 40m and breadth 18m, f
lana [24]

Answer:

Rehan;

76m

Step-by-step explanation:

Distance covered by running around square park :

Perimeter of square = 4s ; s = side length of square

Perimeter = 4 * 42m = 168 m

Total distance covered = 168m * 3 = 504m

Distance covered by running around rectangular park :

Perimeter of rectangle = 2(l + w) ;

Perimeter = 2(40 + 18) = 2(58) = 116 m

Total distance covered = 116m * 5= 580m

580m - 504m = 76m

Rehan covered more distance

4 0
3 years ago
Candice bought 3 shirts.Each shirt Cost the same and was discounted by 3.66.Candice paid a total of 62.31 before tax. How much d
weeeeeb [17]

$21.99 each

1. 3.66+62.31 (since it was discounted)

2. 65.97/3 (for each shirt)

4 0
3 years ago
24 degrees take away -11 degrees
Vilka [71]
13 degrees should be your answer! Hope i helped!
7 0
3 years ago
Read 2 more answers
On James’s MP3 player, he has 12 sad songs and 40 upbeat songs that he wants to put into playlists. He wants to have the same nu
malfutka [58]

Answer:

I think that there needs to be a bit more context for this question

(what are yo currently studying). There are several interoperations that are possible. Do the songs matter, or is it just sad vs happy?

if titles don't matter than I guess the answer would be 12: 1 sad, then 2 sad, then 3 sad, et. up to 12. The happy ones don't matter because there less sad ones.  I think you are wanting to consider "combinations". Once again

the upbeat list should not matter... if you add only one sad song you can have 12 lists. If you add two sad songs the combinations are 66 (see the list)

If you consider all sad song unique quantities, then 4095 would be the total

C(n,r)=(nr)=n!/(r!(n−r)!)

1-12

2-66

3-220

4-495

5-792

6-924

7-792

8-495

9-220

10-66

11-12

12-1

total--4095

Step-by-step explanation:

6 0
3 years ago
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