All categories

3 years ago

By which least number should 12500 10be multiplied to make them perfect squares

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Answer:

The least number 12500 need to be multiplied by to make it a perfect square is 5.

Corrected question;

By which least number should 12500 be multiplied to make them perfect squares

Step-by-step explanation:

Perfect squares are squares of whole numbers.

Like 4,9,16 etc.

For 12500, we need to first of all reduce it to its Lowest factors.

12500 = 2×2×5×5×5×5×5

Grouping the factors into pairs of thesame factors.

12500 = (2×2) × (5×5) × (5×5) × 5

Looking at the pairs of factors, we can observe that the last factor 5 need to be paired to make the number a perfect square.

So, when the number is multiplied by 5;

12500 × 5 = (2×2) × (5×5) × (5×5) × (5×5)

62500 = (2×2) × (5×5) × (5×5) × (5×5)

62500 = (2×5×5×5)^2 = 250^2

Hence, 62500 is a perfect square.

The least number 12500 need to be multiplied by to make it a perfect square is 5.

You might be interested in

Please help me outtttt

QveST [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

When you start from a given set of rules and conditions and determine what must be true you are using _ reasoning

asambeis [7]

Answer:

Deductive

Step-by-step explanation:

4 0

2 years ago

Which expression has a term with a coefficient greater than 1?

Cloud [144]

Answer:

Step-by-step explanation:

3 0

3 years ago

Question Help Of 515515 samples of seafood purchased from various kinds of food stores in different regions of a country and gen

Setler79 [48]

Answer:

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

Step-by-step explanation:

Sample size, n = 51

p = 0.62

1 - p = 1 - 0.62 = 0.38

n = 515

Confidence level = 90% = Zcritical at 90% = 1.645

Confidence interval = (p ± margin of error)

Margin of Error = Zcritical * sqrt[(p(1-p))/n]

Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]

Margin of Error = 1.645 * 0.0214

Margin of Error = 0.035203

Lower boundary = (0.62 - 0.035203) = 0.584797

Upper boundary = (0.62 + 0.035203) = 0.655203

(0.5848 ; 0.6552)

We are confident that about 58% to 66% of sea foods in the country are Mislabelled.

No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

3 0

3 years ago

The cost, C, to produce b baseball bats per day is modeled by the function C(b) = 0.06b2 – 7.2b + 390. What number of bats shoul

kozerog [31]

Check the picture below, that's just an example of a parabola opening upwards.

so the cost equation C(b), which is a quadratic with a positive leading term's coefficient, has the graph of a parabola like the one in the picture, so the cost goes down and down and down, reaches the vertex or namely the minimum, and then goes back up.

bearing in mind that the quantity will be on the x-axis and the cost amount is over the y-axis, what are the coordinates of the vertex of this parabola? namely, at what cost for how many bats?

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ C(b) = \stackrel{\stackrel{a}{\downarrow }}{0.06}b^2\stackrel{\stackrel{b}{\downarrow }}{-7.2}b\stackrel{\stackrel{c}{\downarrow }}{+390} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\bf \left( -\cfrac{-7.2}{2(0.06)}~~,~~390-\cfrac{(-7.2)^2}{4(0.06)} \right)\implies (60~~,~~390-216) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{\textit{number of bats}}{60}~~,~~\stackrel{\textit{total cost}}{174})~\hfill$

6 0

3 years ago