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3 years ago

Can anyone help mewith this probability question.

Mathematics

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

It's 0.72

Step-by-step explanation:

It's independent of gender, so we can ignore the boys and girls part.

Adding the columns, 18 pass and 7 failed the last history test.

Adding those two numbers, you get 25.

So, 25 people took the test, and 18 passed.

You can get the probability by dividing 18 by 25.

Dividing that gives us 0.72

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A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?

olya-2409 [2.1K]

Answer:

x - 6

Step-by-step explanation:

A = L x W

A / L = W

x^2-11x+30 / x -5 = W (Simplify the numerator)

(x - 6) x ( x - 5) / x - 5 = W (Cancel the similar ones which is (x - 5) )

x - 6 = W

Hope that helps

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3 years ago

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How do you solve this don’t mind the (f) that’s just the problem number

zavuch27 [327]

Hello,
You need to evaluate the equation, so:
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3 years ago

. Find the surface area of a sphere with diameter 30 m. Leave your answer in terms of

OlgaM077 [116]

The sphere has surface are of 900π m².

Step-by-step explanation:

Given,

Diameter = d = 30m

Radius = $\frac{d}{2} =\frac{30}{2} = 15m$

Surface area of sphere = $4\pi\ r^2$

$Surface\ area = 4*\pi *(15)^2\\Surface\ area = 4*\pi * 225\\Surface\ area= 990\pi$

The sphere has surface are of 900π m².

Keywords: Surface area, multiplication

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3 years ago

Which of the following is a radical equation?

Nuetrik [128]

The correct answer is B

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3 years ago

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The lengths of two sides of a triangle are 10 and 24, and the third side is x. How many whole number values are possible for x.

solong [7]

Answer:

$20$ .

Step-by-step explanation:

In any triangle, the sum of the lengths of any two sides should be strictly greater than the length of the third side. For example, if the length of the three sides are $a$ , $b$ , and $c$ :

$a + b > c$ ,

$a + c > b$ , and

$b + c > a$ .

In this question, the length of the sides are $10$ , $24$ , and $x$ . The length of these sides should satisfty the following inequalities:

$10 + 24 > x$ ,

$10 + x > 24$ , and

$24 + x > 10$ .

Since $x > 0$ , the inequality $24 + x > 10$ is guarenteed to be satisfied.

Simplify $10 + 24 > x$ to obtain the inequality $x < 35$ .

Similarly, simplify $10 + x > 24$ to obtain the inequality $x > 14$ .

Since $x$ needs to be a whole number, the greatest $x$ that satisfies $x < 35$ would be $34$ . Similarly, the least $x\!$ that satisfies $x > 14$ would be $15$ . Thus, $x\!\!$ could be any whole number between $15\!$ and $34\!$ (inclusive.)

There are a total of $34 - 15 + 1 = 20$ distinct whole numbers between $15$ and $34$ (inclusive.) Thus, the number of possible whole number values for $x$ would be $20$ .

5 0

2 years ago