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koban [17]
3 years ago
15

The sum of 2 composite numbers is never a prime number. Explain your answer.

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

Step-by-step explanation:

Composite numbers are positive numbers that have factors, This means that they are divisible by numbers other than 1 and itself provided that number is a factor of the composite number. They possess at the bearest minimum level, a divisor other than  1 and itself. They are a natural number that is expressible as the product of two(or more) numbers other than 1 and itself.

For example:

4 is a composite number because its factors are 1, 2 and 4 which have another divisor apart from 1 and itself (4). That divisor is 2.

We all know that prime numbers are numbers that can be only be divided by 1 and itself.

Therefore, the sum of two composite number, for example:

4 + 6 = 10, We can now see that 10 is never a prime number.

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A painting crew reported that a job is 3/5 completed. What fraction of the job remains to be done? ​
Debora [2.8K]

Answer:

2/5

Step-by-step explanation:

7 0
2 years ago
Under a dilation, the point (3, 5) is moved to (6, 10).
Vsevolod [243]
The scale factor of the dilation is 2
4 0
3 years ago
Read 2 more answers
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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7 0
2 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.
-BARSIC- [3]

Answer:

Step-by-step explanation:

Hello, please consider the following.

3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

4^n+17 is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so 4^k+17 is divisible by 3

and we check what happens for k+1

4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17

3\cdot 4^k is divisible by 3 and

4^k+17 is divisible by 3, by induction hypothesis

So, the sum is divisible by 3.

Step 3 - Conclusion

We just prove that 4^n+17 is divisible by 3 for all positive integers n.

Thanks

4 0
3 years ago
Rosie bought a car for £4000.
vovangra [49]

Answer:

3.5%

Step-by-step explanation:

4000*3.5% =1400

4000-1400=2600 percentage rosie loss 3.5%

8 0
3 years ago
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