Answer:
(a) 36.36%
(b) 0.36%
(c) 0.06%
Step-by-step explanation:
Given that the time intervals measured with a stopwatch have an uncertainty of about 0.2 s.
We want to know what is the percent uncertainty of a hand-timed measurement of:
(a) 5.5 s
Percentage = (0.2/5.5) × 100
≈ 36.36%
(b) 55 s
Percentage = (0.2/55)×100
≈ 0.36%
(c) 5.5 min
5.5 min = 5.5 × 60 s
= 330 s
Percentage = (0.2/330)×100
≈ 0.06%
Answer: -5/21.
Step-by-step explanation:
![\frac{2}{5}*[\frac{-3}{7} +(\frac{-1}{6})]=\frac{2}{5} *(-\frac{3}{7} -\frac{1}{6}) =\frac{2}{5}*(-\frac{3*6+1*7)}{7*6} )=\frac{2}{5}*(-\frac{18+7}{42})=\frac{2}{5}*(-\frac{25}{42})=-\frac{5}{21} .](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%2A%5B%5Cfrac%7B-3%7D%7B7%7D%20%2B%28%5Cfrac%7B-1%7D%7B6%7D%29%5D%3D%5Cfrac%7B2%7D%7B5%7D%20%2A%28-%5Cfrac%7B3%7D%7B7%7D%20-%5Cfrac%7B1%7D%7B6%7D%29%20%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B3%2A6%2B1%2A7%29%7D%7B7%2A6%7D%20%20%29%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B18%2B7%7D%7B42%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%2A%28-%5Cfrac%7B25%7D%7B42%7D%29%3D-%5Cfrac%7B5%7D%7B21%7D%20.)
Good luck an' have a nice day!
Answer:
below
Step-by-step explanation:


Answer:
V = 5000 + 275*T for simple annual interest
or: A = 5000 * (1.055)^T for an annual compound interest
Step-by-step explanation:
I assume this is a simple interest rate. If not I will give the one for compound interest.
V = 5000 + 5000* 0.055 * T (Value of account after T years)
V = 5000 + 275*T for simple annual interest
or: A = 5000 * (1.055)^T for an annual compound interest
Compare the small marks on the lines of the triangles, if you draw them both out next to each other, are they exactly the same? If so, they’re congruent