The probability that the randomly selected student chose running is; 12/57
<h3>Solving Probability Questions</h3>
Total number of students = 57
Total number of boys = 24
Total number of girls = 33
Number of Girls that chose football = 17
Number of boys that chose football = 14
Number of students that chose Tennis = 14
Now, number of students that chose running will be;
Number of students that chose running = 57 - (31 + 14) = 12
Thus, probability that a randomly selected student chose running = 12/57
Read more about probability selection at; brainly.com/question/251701
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
The parentheses is:

Square the 6 and the 4:

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:

Therefore:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Not sure what you mean by solution since that’s already simplified and inequalities don’t hav coordinate points as solution.
But -4<-3 so that point wouldn’t go into the “shaded area” of that inequality.
Hope this helps
Answer:
Ok since u want to learn ill teach you :)
Get your 3 points and then your do this
Example= 3 power of 2 plus 5 power of 2
Then ur gonna add and get your answer hope this helps
(if u still don't get it ill just give u the answer)
7.2
Step-by-step explanation:
Hope u kinda got a good start on this :)
Step-by-step explanation:
5/4+(12/4_1/2)^2
5/4+((12_8)/4)^2
5/4+1
9/4