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svlad2 [7]
3 years ago
10

A Lake Tahoe Community College instructor is interested in the mean number of days Lake Tahoe Community College math students ar

e absent from class during a quarter.
1. What is the population she is interested in?a. all Lake Tahoe Community College studentsb. all Lake Tahoe Community College English studentsc. all Lake Tahoe Community College students in her classesd. all Lake Tahoe Community College math students
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

d.

Step-by-step explanation:

Hello!

The population is the set of elements that you are interested in studying. In this example, the instructor wants to know the number of days Lake Tahoe Community College math students are absent from class during a quarter. To do so she will take a random sample of math students and register the number of absences of each student. Each math student is an element of the population.

Then the population is "Lake Tahoe Community College math students"

I hope it helps!

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a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

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Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

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<u>Alternative hypothesis H1:</u>- p1 ≠ p2

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Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

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assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

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Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

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