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erica [24]
4 years ago
14

Suppose I collected a sample and calculated the sample proportion. If I construct a 90% confidence interval for the population p

roportion and a 95% confidence interval for the population proportion, which of these intervals will be wider?'
Mathematics
1 answer:
Daniel [21]4 years ago
3 0

Answer:

Step-by-step explanation:

If you construct a 90% confidence interval for the population proportion and a 95% confidence interval for the population proportion, the 95% confidence will have a wider interval. This is because a higher confidence interval will provide more possible values from which the true value will be determined. Therefore, If you want more confidence that an interval contains the true parameter, then the intervals will be wider.

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Please help me if you can. Please also write how you got the answer thank you.
vlabodo [156]

Answer:

1 <= n <= 3

Step-by-step explanation:

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draw a line from the lower point to the upper number line

thats what n can be

7 0
3 years ago
6 erasers cost $6.60. Which equation would help determine the cost of 3 erasers?
AveGali [126]

Answer:

3(6.60/6)

Step-by-step explanation:

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3 years ago
!!!!!PLEASE HELP!!!!!<br> *30 POINTS PLEASE*
Lelechka [254]

Answer:

Part 1)

Part a) Yes, triangle ABC is congruent with triangle DEC by SAS

Part b) No, triangle ABC is not congruent with triangle DCE

Part 2) No, is not enough information

Part 3) Yes, triangle RST is congruent with triangle VUT by ASA

Part 4) Yes, triangle DEF is congruent with triangle DHG by SAS

Step-by-step explanation:    

Part 1) we have two cases

Part a) Is triangle ABC and DEC congruent?

Yes, triangle ABC is congruent with triangle DEC by SAS

we know that

The <u><em>Side Angle Side postulate</em></u> ( SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent

In this problem

AC≅DE

BC≅EC

and

∠ACB≅∠DCE  ---> by vertical angles

Part b) Is triangle ABC and DCE congruent?

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

In this problem

the corresponding sides are not congruent

because

AB is not congruent with DC

Part 2) we have that

No, is not enough information

If AC≅XZ then the triangles ABC and XYZ will be congruent by SSS

or

If ∠ABC≅∠XYZ then the triangles ABC and XYZ will be congruent by SAS

Part 3) we have that

Yes, triangle RST is congruent with triangle VUT by ASA

we know that

If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle -Side-Angle (ASA) postulate

In this problem

ST≅UT

∠RST≅∠VUT ----> is a right angle

∠RTS≅∠VTU ---->by vertical angles

so

Two angles and the included side are the same in both triangles

therefore

triangles RST and VUT are congruent by ASA

Part 4) we have that

Yes, triangle DEF is congruent with triangle DHG by SAS

we know that

The <u><em>Side Angle Side postulate</em></u> ( SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent

In this problem

DE≅DH

DF≅DG

and

∠EDF≅∠HDG  ---> by vertical angles

7 0
3 years ago
What are the solutions of x^2 = -7x-8
Vilka [71]

Solution, solve\:for\:x,\:x^2=-7x-8\quad :\quad x=\frac{-7+\sqrt{17}}{2},\:x=\frac{-7-\sqrt{17}}{2}

Steps:

x^2=-7x-8

\mathrm{Add\:}8\mathrm{\:to\:both\:sides},\\x^2+8=-7x-8+8

\mathrm{Simplify},\\x^2+8=-7x

\mathrm{Add\:}7x\mathrm{\:to\:both\:sides},\\x^2+8+7x=-7x+7x

\mathrm{Simplify},\\x^2+7x+8=0

Solve\:with\:the\:quadratic\:formula,\\\mathrm{For\:}\quad a=1,\:b=7,\:c=8:\quad x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1},\\x=\frac{-7+\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7+\sqrt{17}}{2},\\x=\frac{-7-\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7-\sqrt{17}}{2}

\mathrm{The\:final\:solutions\:to\:the\:quadratic\:equation\:are:},\\x=\frac{-7+\sqrt{17}}{2},\:x=\frac{-7-\sqrt{17}}{2}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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weqwewe [10]
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