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3 years ago

Probability: If you roll a regular 6-faced die 1200 times, about how many times would you expect to get a 4?

Mathematics

2 answers:

Gre4nikov [31]3 years ago

8 0

Answer:

200

Step-by-step explanation:

Divide 1200 by 6.

just olya [345]3 years ago

6 0

If you roll a six sided dice once, each outcome has a 1/6 probability.

This means 4 has a 1/6 probability.

If you roll a dice 1200 times....

1200 × 1/6 = 1200/6 = 200

You would expect to get a 4 200 times.

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HELP ASAP MATH QUESTION WILL BE MARKED BRAINLIESTTT!! PART ! FR THIS TIME

olganol [36]

Answer:

length, width , and perimeter

Step-by-step explanation:

27 8

3 0

3 years ago

Write the equation of the conic section with the given properties:

timurjin [86]

Answer:

$\frac{x^2}{64} + \frac{y^2}{25} =1$

Step-by-step explanation:

An ellipse with vertices (-8, 0) and (8, 0)

Distance between two vertices = 2a

Distance between (-8,0) and (8,0) = 16

2a= 16

so a= 8

Vertex is (h+a,k)

we know a=8, so vertex is (h+8,k)

Now compare (h+8,k) with vertex (8,0) and find out h and k

h+8 =8, h=0

k =0

a minor axis of length 10.

Length of minor axis = 2b

2b = 10

so b = 5

General formula for the equation of horizontal ellipse is

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b} =1$

a= 8 , b=5 , h=0,k=0. equation becomes

$\frac{(x-0)^2}{8^2} + \frac{(y-0)^2}{5} =1$

$\frac{x^2}{64} + \frac{y^2}{25} =1$

5 0

3 years ago

at a concert 25% of the audience members were teenagers. if the number of teenagers at the concert was 120, what was the total n

klemol [59]

The total number of audience members is 480

3 0

3 years ago

Read 2 more answers

La familia Sánchez Olguín, quiere terminar de construir su casa y necesita S/.25000 para todos los gastos del acabado de la casa

erastova [34]

Extraemos los datos del problema:

Capital Inicial → C₀ = S/.25000
Interés bimestral → i = 8 % = 0.08
Periodos → n = 3

<h2 /><h2>Bimestre 1:</h2>

Capital Inicial Bimestre → C = S/.25000

Tasa de interés bimestral:

I = C×i

I = S/.25000 × 0.08

I = S/.2000

Monto final:

M = C + I

M = S/.25000 + S/.2000

M = S/.27000

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 27000 - 25000) / 25000

% = 8

<h2>Bimestre 2:</h2>

Capital Inicial Bimestre → C = S/.27000

Tasa de interés bimestral:

I = C×i

I = S/.27000 × 0.08

I = S/.2160

Monto final:

M = C + I

M = S/.27000 + S/.2160

M = S/.29160

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 29160 - 25000) / 25000

% = 16.64

<h2>Bimestre 3:</h2>

Capital Inicial Bimestre → C = S/.29160

Tasa de interés bimestral:

I = C×i

I = S/.29160 × 0.08

I = S/.2332.8

Monto final:

M = C + I

M = S/.29160 + S/.2332.8

M = S/ 31492.8

Variación Porcentual:

% = (M - C₀) / C₀

% = ( 31492.8 - 25000) / 25000

% = 25.97

7 0

3 years ago

A fivey sequence is a sequence of positive integers which adds up to 5. For example, 2, 2, 1 and 2, 1, 2 are two different fivey

vlabodo [156]

The total number of possible fivey sequences are; 6

<h3>How to solve a sequence?</h3>

We are told we are dealing with a fivey sequence which means that all the terms of the sequence must be positive integers and they must add up to 5.

Now, the possible numbers that can be used are;

1, 2 and 3.

If we start with 3, number of possible sequences is; 1

If we start with1, number of possible sequences is; 3 ways

If we start with 2, number of possible sequences is; 2 ways

Thus;

Total number of fivey sequences is 1 + 2 + 3 = 6 possible sequences

Read more about Sequence at; brainly.com/question/13612968

#SPJ1

4 0

2 years ago

Probability: If you roll a regular 6-faced die 1200 times, about how many times would you expect to get a 4?​

Probability: If you roll a regular 6-faced die 1200 times, about how many times would you expect to get a 4?