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22. Okay. What we need to do for this one is subtract fraction.l, because we are looking for how much more the second container holds than the first. We need to covert them to like denominators, which in this case is 8 5 3/4 = 5 6/8. Because 6/8 is less than 7/8, we need to regroup by adding 8 and turning the 5 into a 4. The problem would become like this: 4 14/8 - 1 7/8. When you subtract both numbers, you get 3 7/8. There. The second container holds 3 7/8 more gallons of water than the first.
23.
a. 15 student speeches will last 1 1/2 minutes each. In this case, we just simply multiply the fractions by multiply straight across. Multiply the top numbers together and the bottom numbers together. 1 1/2 is 3/2 a an improper fraction. Make 15 have a denominator of 1. 15/1 * 3/2 is 45/2 or 22 1/2 as a mixed number. It will take 22 1/2 minutes to give the speeches.
b. Okay. The teacher makes a 15 minute intro. Let’s add the time it takes to make the speeches and the teacher’s intro. 22 1/2 + 15 0/2 is 37 1/2. Yes. There is enough time to record everyone.
c. There are 60 minutes in 1 hour. Subtract the total amount taken on the camera from 60. 0/2 is less than 1/2. Again, regroup by adding 2 to make 2/2, and crossing out 60, so it becomes 59. 59 2/2 - 37 1/2 is 22 1/2. There are 22 1/2 minutes left on the digital camera.
Answer:
X=0
Step-by-step explanation:
An acite becaues it lowers than the others
Given inequality : 175 ≤ 3x-17 ≤ 187, where x represents the height of the driver in inches.
Let us solve the inequality for x.
We have 17 is being subtracted in the middle.
Reverse operation of subtraction is addition. So, adding 17 on both sides and also in the middle, we get
175+17 ≤ 3x-17+17 ≤ 187+17
192 ≤ 3x ≤ 204.
Dividing by 3.
192/3 ≤ 3x/3 ≤ 204/3.
64 ≤ x ≤ 68.
Therefore, the height of the driver should be from 64 to 68 inches to fit into the race car.
