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3 years ago

Hi people of earth... I have a question here...

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

Hello person who is also from earth :)

6 - -4 = 10

Have a good day!!

Zielflug [23.3K]3 years ago

3 0

The answer is 10, 6 - -4=10

=6--4
=6+4
=10.

I hope this helps!

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A technical machinist is asked to build a cubical steel tank that will hold of water. Calculate in meters the smallest possible

Charra [1.4K]

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

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Required

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$Volume = Length^3$

This gives:

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$\frac{565m^3}{1000} = Length^3$

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$0.8267m = Length$

Rewrite as:

$Length = 0.8267m$

Approximate

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2 years ago

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Answer:

Step-by-step explanation:

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2 years ago

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2 years ago

What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?

Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

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We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by

$P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now,

$\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}$

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