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3 years ago

Hello can you please help me posted picture of question

Mathematics

2 answers:

ASHA 777 [7]3 years ago

7 0

The correct answer is A because a(in the equation) dictates slope and, if negative, think opposite

11Alexandr11 [23.1K]3 years ago

6 0

Since the squared term is x the parabola can either open or down. If the square was on y term, the parabola would have open right or left.

The sign of the leading term determines the direction of opening. If leading term is positive and squared term is x, the parabola opens up and if the leading term is negative the parabola opens down.

Since a is negative the parabola opens down.

So the correct answer to this question is option A

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Find the area of the shaded shape pls quickly

professor190 [17]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Area of shaded region is equal to :

Area of rectangle - Area of two triangles ~

1. Area of rectangle :

$\qquad \sf \dashrightarrow \: length \times width$

$\qquad \sf \dashrightarrow \: 20 \times 15$

$\qquad \sf \dashrightarrow \: 300 \: \: cm {}^{2}$

2. Area of first triangle :

$\qquad \sf \dashrightarrow \: \cfrac{1}{2} \times (base) \times (height)$

$\qquad \sf \dashrightarrow \: \cfrac{1}{2} \times (20 - 18) \times (15)$

$\qquad \sf \dashrightarrow \: \cfrac{1}{2} \times (2) \times (15)$

$\qquad \sf \dashrightarrow \: 15 \: \: cm {}^{2}$

3. Area of second triangle :

$\qquad \sf \dashrightarrow \: \cfrac{1}{2} \times (base) \times (height)$

$\qquad \sf \dashrightarrow \: \cfrac{1}{2} \times (6) \times(20)$

$\qquad \sf \dashrightarrow \: 3 \times 20$

$\qquad \sf \dashrightarrow \: 60 \: \: cm {}^{2}$

Area of shaded region is :

$\qquad \sf \dashrightarrow \: 300 - (15 + 60)$

$\qquad \sf \dashrightarrow \: 300 - 75$

$\qquad \sf \dashrightarrow \: 225 \: \: cm {}^{2}$

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Step-by-step explanation:

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3 years ago

What is the domain of validity for csc theta =

My name is Ann [436]

For the three basic trig identities (sin, cos, tan) there are three more which act as their reciprocals (csc, sec, and cot respectively)

A reciprocal of x can be represented as 1/x.
Therefore, cscӨ can also be represented as the reciprocal of sinӨ...1/sinӨ.

In that case, our answer should always be true so long as we put in a real number for theta, because that's the domain of sinӨ, right? However, we also have to satisfy the domain of cscӨ, and the limitations become extremely obvious when you look at this reciprocal identity equation...sinӨ cannot be zero because it is impposible to divide by zero! Looking at the unit circle, any multiple of π will make sin<span>Ө = 0, so there's your answer.
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Setler79 [48]

Answer:25

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Galina-37 [17]

Slope is 3
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