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Studentka2010 [4]
3 years ago
14

Someone please help

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

Im sorry im not sure how to do this either lol :/

Step-by-step explanation:

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A coin has two sides head and tails a die has six sides if you roll the die what is the probability that you flip heads and roll
weqwewe [10]

Using it's concept, the probability that you flip heads and roll a number greater than 5 is: \frac{1}{12}.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, we have that:

  • The probability of a head is 1/2.
  • The probability of a number greater than 5 is 1/6.

Hence the probability of both events is:

p = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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2 years ago
What is 7 1/2 inches as a decimal of 1 foot
enyata [817]

Answer:

7 1/2 inches as a decimal of 1 foot is 0.625ft

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1<br> Find the value of x.<br> 117°<br> 1940<br> to
kotykmax [81]

Answer:

X= 23 degrees

Step-by-step explanation:

117 degrees minus 94 equals x

x=23

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2 years ago
Graph at least four points from the rule y=2x+1
goldfiish [28.3K]

Y=2x1+2+1=5

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3 years ago
(1 point) Let p be the joint density function such that p(x,y)=116xy in R, the rectangle 0≤x≤4,0≤y≤2, and p(x,y)=0 outside R. Fi
baherus [9]

Answer:

The answer is \frac{7}{8} of the population.

Step-by-step explanation:

The question is wrong. The joint density function is p(x,y)=(\frac{1}{16})xy in R

and p(x,y)=0 outside R.

R is defined as the rectangle 0\leq x\leq 4 , 0\leq y\leq 2

In order to find the fraction of the population satisfying the constraint x\geq y , we will need to integrate the joint density function p(x,y) over the region defined by the constraint. It is very convenient to draw the region ''R'' and the new region define by the constraint x\geq y

I will attach a drawing with the region ''R'' and the new region where we need to apply the integral.

If we integrate outside ''R'', given that p(x,y)=0 outside ''R'', the integral will be equal to 0 (because of the joint density function).

Inside the rectangle ''R'' and given the constraint x\geq y , we define two new regions : the green region (I) and the blue region (II).

The final step is to integrate in (I) and in (II) and sum ⇒

\int\int p(x,y) dx dy ⇒

\int \int\limits_1 {p(x,y)} \, dx dy + \int \int\limits_2{p(x,y)} \, dx dy , where ''1'' is the green region and ''2'' is the blue region.

⇒ \int\limits^2_0 \int\limits^x_0 (\frac{1}{16} xy) dy dx   +  \int\limits^4_2\int\limits^2_0 (\frac{1}{16}xy) dydx  = \frac{1}{8}+\frac{3}{4}=\frac{7}{8}=0.875

We find that \frac{7}{8} of the population satisfy the constraint x\geq y.

6 0
3 years ago
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