Answer:
The rock splashes down when h(t) = 0. Set h(t) = 0 and solve for t using quadratic formula.
0 = − 4.9t^2 + 178t + 325
t = 38.07, -1.74
(Throw away the negative answer, since time can't be negative.)
t = 38.07 sec
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Answer:
-6/7 < -1/7
because it is more than negative one by seven
I believe that the answer is 13
Answer:
Neither parallel nor perpendicular
Step-by-step explanation:
I'm assuming you meant line k is y = 3x -2. If not, this is wrong.
For this, you need to put both lines in point-slope form, or the form that line k is already in. This means you only need to convert line m.
-2r + 6v = 18
6v = 2r + 18
v = 2/6r + 18/6
v = 1/3r + 3
Now you can answer the question.
To be parallel, lines must have the same slope (but a different y-intercept). 3 and 1/3 are not the same, so the lines are not parallel.
To be perpendicular, one line must have the opposite reciprocal (fraction flipped and + goes to - or - to +) of the other. While 3 is the reciprocal of 1/3, they are both positive, so they are not perpendicular.
To be the same line, the equations must be absolutely identical, which they aren't.
This leaves the last option: neither.
Let me know if you need a more in-depth explanation of anything here! I'm happy to help!
Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
