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olga nikolaevna [1]
2 years ago
12

1 4/9 + 2 6/9 is equal to 4 1/9 True or False?​

Mathematics
2 answers:
Law Incorporation [45]2 years ago
7 0

Answer:

True

Step-by-step explanation:

4/9+6/9= 10/9=1 1/9

2+1=3

3+1 1/9=4 1/9

Thepotemich [5.8K]2 years ago
4 0

Answer:

True

Step-by-step explanation:

1 4/9 +2 6/9 add the whole numbers 1+2

3 +4/9+6/9 and the fractions. 3+10/9 simplify 3+1 1/9 4 1/9

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A submarine descends at a rate of 2.6 kilometers per hour.
kotegsom [21]

Answer:

6.24/2.6 = 0.24

0.2 is the answer

Step-by-step explanation:

3 0
2 years ago
If UV = x+8, VW = 6x-8, and UW=14, what is VW?
Agata [3.3K]

Answer:

VW=4\ units

Step-by-step explanation:

step 1

Find the value of x

In this problem i will assume that  U,V and W are collinear and V is between U and W

so

UW=UV+VW ----> by addition segment postulate

substitute the given values

14=(x+8)+(6x-8)

solve for x

14=7x

x=2

step 2

Find the value of VW

VW=(6x-8)

substitute the value of x

VW=(6(2)-8)=4\ units

3 0
3 years ago
What is 15 less than or equal to -5x​
lara [203]

Answer:

less than tell me if i'm wrong

4 0
3 years ago
Let x be the weight of a juvenile condor. Write the possible unique values for x: (NOTE: Separate each value in the list with a
larisa86 [58]

MISSING PART OF QUESTION:

Consider the population of four juvenile condors. Their weights in pounds are : 5, 6, 10, 13

Answer:

The unique weights are 5, 6, 10 and 13

Step-by-step explanation:

Given

Weights: 5, 6, 10, 13 pounds

Required

Determine the unique weights of the juvenile

From the question, we understand that the weights of the juveniles could be any of 5 pounds, 6, 10 or 13 pounds

These values are the unique weights of the juveniles.

In other words, any value other than 5, 6, 10 or 13 can not be regarded as weights of the juveniles.

Hence, the unique weights are 5, 6, 10 and 13

8 0
2 years ago
Solve the formula A=lw for l
agasfer [191]

Answer:

I=\frac{A}{w}

Step-by-step explanation:

Given A=Iw

Divide both side by w.

\frac{A}{w}=\frac{Iw}{w}\\\\\frac{A}{w}=I\\\\I=\frac{A}{w}

7 0
3 years ago
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