Answer:
The mass percentage is 3.26 %.
Explanation:
The reaction between acetic acid and NaOH will be:
![CH_{3}COOH + NaOH--->CH{3}COONa+H_{2}O](https://tex.z-dn.net/?f=CH_%7B3%7DCOOH%20%2B%20NaOH---%3ECH%7B3%7DCOONa%2BH_%7B2%7DO)
Thus one mole of acetic acid will react with one mole of NaOH.
The moles of NaOH used = molarity X volume = 0.1 X 30.10 mL = 3.010 mmol
The moles of acetic acid reacted = 3.010 mmol
The moles of acetic acid will be used to calculate the mass of acetic acid used
Mass of acetic acid used = moles X molar mass = 3.010mmol X 60
mass of acetic acid used = 180.6 mg = 0.1806 g
The mass of vinegar used = 5.54 g
The percentage of acetic acid in vinegar will be =
%