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VikaD [51]
4 years ago
5

What type of bond between water molecules pulls them into this tight ball?

Chemistry
1 answer:
jonny [76]4 years ago
6 0
A water molecule contains an oxygen atom and two hydrogen atoms which are covalently bonded to the oxygen atom.Atoms in a covalently bonded molecule are always fighting for the shared electrons, the atoms attraction to the shared electrons is called the electronegativity. Therefore, the more electronegative an atom is the more it attracts the shared electrons.The  force of attraction between a partially electronegative atom and another partially positive atom is the hydrogen bond. It is the hydrogen bond that pulls water molecules together which results into a cohesive force between the water molecules.
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A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate th
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Complete question:

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.

Answer:

the heat of combustion of the methanol is 402.31 kJ/mol

Explanation:

Given;

mass of water, m_w = 100 g

initial temperature of water, t₁ = 28 ⁰C

final temperature of water, t₂ = 58 ⁰C

specific heat capacity of water = 4.184 J/g⁰C

reacting mass of the methanol, m = 1.00 g

molecular mass of methanol = 32.04 g/mol

number of moles = 1 / 32.04

                             = 0.0312 mol

Apply the principle of conservation of energy;

n\Delta H_{methanol} = Q_{water}\\\\n\Delta H_{methanol} =  mc\Delta t\\\\n\Delta H_{methanol} =  100 \times 4.184\times (58-28)\\\\n\Delta H_{methanol} =  12,552 \ J\\\\n\Delta H_{methanol} =  12.552 \ kJ\\\\\Delta H_{methanol} = \frac{12.552}{n} \\\\H_{methanol} = \frac{12.552 \ kJ}{0.0312 \ mol} \\\\\Delta H_{methanol} = 402.31 \ kJ/mol

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol

                       

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3 years ago
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