I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Can you say what is the line between the 14 and 8
Answer:
The amount after 6 months compounded quarterly is $1917.66 .
Step-by-step explanation:
Given as :
The principal amount deposited in account = $1850
The bank applied rate of interest = r = 7.25% compounded quarterly
The time period of loan = t = 6 months = 0.5 years
Let the Amount after 6 months = $A
Now,<u> From quarterly Compound Interest method </u>
Amount = principal × 
Or, A = p × 
Or, A = $1850 × 
Or, A = $1850 × 
Or, A = $1850 × 1.036578
∴ A = $1917.66
i.e A = $1917.66
So, The amount after 6 months = A = $1917.66
Hence, The amount after 6 months compounded quarterly is $1917.66 . Answer
Hope you could understand.
If you have any query, feel free to ask.