Question

A circle is centered at the point (5,-4) & passes through the point (-3,2).

Answer 1

Equation of the circle:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

The equation of a circle is given by

$(x-x_0)^2+(y-y_0)^2=r^2$

where

$(x_0,y_0)$ are the coordinates of the center of the circle

r is the radius of the circle

For the circle in this problem, we know that:

(5,4) are the coordinates of the center

We also know that the circle passes through the point (-3,2), therefore we can calculate the radius as the distance between the point on the circle and the center of the circle:

$r=\sqrt{(-3-(5))^2+(2-(-4))^2}=\sqrt{(-8)^2+(6)^2}=\sqrt{64+36}=10$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=10^2\\(x-5)^2+(y+4)^2=100$

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