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galben [10]
3 years ago
14

The origin is contained in the solution set of:

Mathematics
1 answer:
user100 [1]3 years ago
7 0
Y<1/2x+1 is true..............................
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A new basketball cost $25.90 and is half-price today only. What is the price you will pay, exluding tax? $
e-lub [12.9K]

Answer:

$12.95

Step-by-step explanation:

25.9 divided by 2 = 12 .95

5 0
2 years ago
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Match the absolute value equation with its graph without solving the equation.<br><br> |x+2|=4
Dafna11 [192]
The third one, the distance from -2 needs to be 4
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4 years ago
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Joãozinho de Gitana calculadora o número de 12750 Qual é o número que tempo para subtrair para obter como resultado o número 122
Aliun [14]

Responder:

500

Explicação passo a passo:

O número a subtrair de 12.750 em outro para obter 12.250

Deixe o número = x

Isso é ; se x for subtraído de 12750; nós obtemos 12250

12750 - x = 12.250

Subtraia 12750 de ambos os lados

12750 - x - 12750 = 12.250 - 12750

-x = - 500

x = 500

8 0
3 years ago
If the radius of a sphere is increased by 5 cm so that the area of the sphere obtained is increased by 400pi square cm. What was
Sliva [168]

Answer:

The answer is 314cm²

the formula for the sphere area of a sphere is:

A= 4TT²

A = 4x3.14x5²

first solve for exponents

A = 4x 3.14x25

then multiply

A = 314cm²

8 0
3 years ago
What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m
Shtirlitz [24]

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg

Thus, the mass of the solid ball of iron is 60.6528 kg

8 0
3 years ago
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